Can I write a narrative writing how the first time I fell in love with blue eyes?

an open tank has the shape of a right circular cone (see figure). the tank is 8 feet across the top and 6 feet high. how much wo

Liono4ka [1.6K]

The amount of work done in emptying the tank by pumping the water over the top edge is 163.01* 10³ ft-lbs.

Given that, the tank is 8 feet across the top and 6 feet high

By the property of similar triangles, 4/6 = r/y

6r = 4y

r = 4/6*y = 2/3*y

Each disc is a circle with area, A = π(2/3*y)² = 4π/9*y²

The weight of each disc is m = ρw* A

m = 62.4* 4π/9*y² = 87.08*y²

The distance pumped is 6-y.

The work done in pumping the tank by pumping the water over the top edge is

W = 87.08 ∫(6-y)y² dy

W = 87.08 ∫(6y³ - y²) dy

W = 87.08 [6y⁴/4 - y³/3]

W = 87.08 [3y⁴/2- y³/3]

The limits are from 0 to 6.

W = 87.08 [3*6⁴/2 - 6³/3] = 87.08* [9*6³ - 2*36] = 87.08(1872) = 163013.76 ft-lbs

The amount of work done in emptying the tank by pumping the water over the top edge is 163013.76 ft-lbs.

To know more about work done:

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7 0

2 years ago

If a light is moved twice (2x) as far from a surface, the area the light covers is ___ as big.

Serga [27]

Answer:

The correct option is;

- 4x

Explanation:

From the inverse square law, as the distance from the source of a physical quantity increases, the intensity of the source is spread over an area proportional to the square of the distance of the object from the source

The inverse square law can be presented as follows;

$I = \dfrac{S}{4\times \pi \times r^2 }$

As the distance, r, increases, the surface it covers also increases by the power of 2

Therefore, where the distance increases from r to 2·r, we have;

When, I, remain constant

$I = \dfrac{4\times S}{4\times \pi \times (2\cdot r)^2 } = I = \dfrac{4\times S}{4\times 4\times \pi \times r^2 } = \dfrac{S}{4\times \pi \times r^2 }$

The surface increases to 4·S by the inverse square law

Therefore, the correct option is 4 × x.

3 0

3 years ago

Two trains, each having a speed of 28 km/h, are headed at each other on the same straight track. A bird that can fly 60 km/h fli

Semenov [28]

Answer:

The value is $D = 70.71 \ km$

Explanation:

From the question we are told that

The speed of each train is $v = 28 \ km/h$

The speed of the bird is $v_1 = 60 \ km/h$

The distance between the trains is $d = 66 \ km$

Generally the time taken before the collision occurs is mathematically represented as

$t = \frac{d}{2 * v}$

=> $t = \frac{66 }{2 * 28}$

=> $t = 1.18 \ h$

The total distance covered by the bird is mathematically represented as

$D = v_1 * t$

=> $D = 60 * 1.18$

=> $D = 70.71 \ km$

7 0

3 years ago

A space shuttle orbits Earth at a speed of 21,000 km/hr. How far does it go in 3.5 hrs?

inn [45]

Since it travels at 21,000 kilometers per hour, you'd just multiply that with 3.5 to get 73,500. So your answer is 73,500.

5 0

4 years ago

20 POINTS! Two similar solids have heights of 6 cm and 9 cm. If the volume of the smaller solid is 88 cm^3, calculate the volume

dexar [7]

Answer: $132cm^{3}$

Explanation:

The volume $V$ of a solid is given by the multiplication of its three dimensions:

$V=(height)(widgth)(length)$

In this case we have two similar solids with volumes $V_{1}=88cm^{3}$ and $V_{2}$ , and we only have information about the height of each solid $h_{1}=6cm$ and $h_{2}=9cm$ .

Now, there is a theorem for similar solids, which establishes the ratio of their volume is $\frac{V_{1}}{V_{2}}$ and the ratio of one of their corresponding sides (the height in this case) is $\frac{h_{1}}{h_{2}}$ .

Knowing this, we can write the following relation:

$\frac{V_{1}}{V_{2}}=\frac{h_{1}}{h_{2}}$

Substituting the known values:

$\frac{88cm^{3}}{V_{2}}=\frac{6cm}{9cm}$

Fially finding $V_{2}$ :

$V_{2}=132cm^{3}$

8 0

3 years ago