Answer:
The velocity of the second ball after the collision will be 16.3 m/s.
Step-by-Step Explanation:
Law of conservation of momentum states that the total momentum of an isolated remains the same before and after the collision.
Let: mass of the first ball = m1 = 1.5 kg
mass of the second ball = m2 = 2.3 kg
Momentum before the collision:
velocity of the first ball = v1 = 25 m/s
velocity of the second ball = v2 = 0 m/s
[tex] Initial momentum = m1v1 + m2v2 = 1.5*25 + 2.3*0 = 37.5 kgm/s [\tex]
Momentum after the collision:
velocity of the first ball = v1 = 0 m/s
velocity of the second ball = v2 = x
[tex]momentum after the collision= m1v1 + m2v2 = 1.5*0 + 2.3*x = 2.3*x[\tex]
According to law of conservation of momentum:
Initial momentum = Momentum after collision
37.5 = 2.3*x
⇒ x = 37.5/2.3
x = 16.3 m/s
