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soldier1979 [14.2K]
3 years ago
6

If the force on an object is in the negative direction, the work it does on the object must be:.

Physics
2 answers:
Inga [223]3 years ago
6 0

Answer:

The work could be either positive or negative, depending on the direction the object moves

Explanation:

topjm [15]3 years ago
5 0
The work done is also in the negative direction
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3 years ago
Receiving delicious food is to escaping electric shock as ________ is to ________.
Aleks [24]

Answer:

positive reinforcer; negative reinforcer

Explanation:

positive reinforcer; negative reinforcer

Receiving delicious food can be seen as a positive reinforcer while escaping electric shock can be seen as a negative reinforcer.

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3 years ago
According to the general theory of relativity, what are consequences of the curvature of space-time? Check all that apply. The d
Svetlanka [38]

Answer:

The dilation of time.

The falling of objects.

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From the explanation, the correct ones are;

The dilation of time.

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4 0
3 years ago
What is the speed of a beam of electrons when under the simultaneous influence of E = 1.64×104 V/m B = 4.60×10−3 T Both fields a
andrezito [222]

Answer: v = 3.57×10^6 m/s; R = 4.42×10^-3m; T = 7.78×10^-9 s

Explanation:

Magnetic force(B) = 4.60×10^-3 T

Electric force(E) = 1.64×10^4 V/m

Both forces having equal magnitude ;

Magnetic force = electric force

qvB = qE

vB = E

v = (1.64×10^4) ÷ (4.60×10^-3)

v = 3.57×10^6 m/s

2.) Assume no electric field

qvB = ma

Where a = v^2 ÷ r

R = radius

a = acceleration

v = velocity

qvB = m(v^2 ÷ R)

R = (m×v) ÷ (|q|×B)

q=1.6×10^-19C

m = 9.11×10^-31kg

R = (9.11×10^-31 * 3.57×10^6) ÷ (1.6×10^-19 * 4.6×10^-3)

R = 32.5227×10^-25 ÷ 7.36×10^-22

R = 4.42×10^-3m

3.) period(T)

T = (2*pi*R) ÷ v

T = (2* 4.42×10^-3 * 3.142) ÷ (3.57×10^6)

T = (27.775×10^-3) ÷(3.57×10^6)

T = 7.78×10^-9 s

6 0
4 years ago
Will mark the brainliest
AysviL [449]

Answer:

The impulse transferred to the nail is 0.01 kg*m/s.

Explanation:

The impulse (J) transferred to the nail can be found using the following equation:

J = \Delta p = p_{f} - p_{i}

Where:                                                                

p_{f}: is the final momentum

p_{i}: is the initial momentum

The initial momentum is given by:

p_{i} = m_{1}v_{1_{i}} + m_{2}v_{2_{i}}

Where 1 is for the hammer and 2 is for the nail.

Since the hammer is moving down (in the negative direction):

v_{1_{i}} = -10 m/s

And because the nail is not moving:

v_{2_{i}}= 0                      

p_{i} = m_{1}v_{1_{i}} = 0.25 kg*(-10 m/s) = -2.5 kg*m/s

Now, the final momentum can be found taking into account that the hammer remains in contact with the nail during and after the blow:

p_{f} = m_{1}v_{1_{f}} + m_{2}v_{2_{f}}

Since the hammer and the nail are moving in the negative direction:

v_{1_{f}} = v_{2_{f}} = -9.7 m/s

p_{f} = -9.7 m/s(7 \cdot 10^{-3} kg + 0.25 kg) = -2.49 kg*m/s

Finally, the impulse is:

J = p_{f} - p_{i} = - 2.49 kg*m/s + 2.50 kg*m/s = 0.01 kg*m/s

Therefore, the impulse transferred to the nail is 0.01 kg*m/s.

I hope it helps you!                                                                                                                                                                                                                                                                                                                                                                                                                    

7 0
3 years ago
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