Hello!
Data:
Molar Mass of H2CO3 (carbonic acid)
H = 2*1 = 2 amu
C = 1*12 = 12 amu
O = 3*16 = 48 amu
------------------------
Molar Mass of H2CO3 = 2 + 12 + 48 = 62 g/mol
Now, since the Molarity and ionization constant has been supplied, we will find the degree of ionization, let us see:
M (molarity) = 0.01 M (Mol/L) → 
Use: Ka (ionization constant) = 










Now, we will calculate the amount of Hydronium [H3O+] in carbonic acid (H2CO3), multiply the acid molarity by the degree of ionization, we will have:
![[ H_{3} O^+] = M* \alpha](https://tex.z-dn.net/?f=%20%5B%20H_%7B3%7D%20O%5E%2B%5D%20%3D%20M%2A%20%5Calpha%20%20)
![[ H_{3} O^+] = 1*10^{-2}* 2.09*10^{-5}](https://tex.z-dn.net/?f=%20%5B%20H_%7B3%7D%20O%5E%2B%5D%20%3D%201%2A10%5E%7B-2%7D%2A%202.09%2A10%5E%7B-5%7D%20)
![[ H_{3} O^+] = 2.09*10^{-2-5}](https://tex.z-dn.net/?f=%20%5B%20H_%7B3%7D%20O%5E%2B%5D%20%3D%202.09%2A10%5E%7B-2-5%7D%20)
![\boxed{[ H_{3} O^+] = 2.09*10^{-7}}](https://tex.z-dn.net/?f=%20%5Cboxed%7B%5B%20H_%7B3%7D%20O%5E%2B%5D%20%3D%202.09%2A10%5E%7B-7%7D%7D%20)
And finally, we will use the data found and put in the logarithmic equation of the PH, thus:
Data:

![[ H_{3} O^+] = 2.09*10^{-7}](https://tex.z-dn.net/?f=%20%5B%20H_%7B3%7D%20O%5E%2B%5D%20%3D%202.09%2A10%5E%7B-7%7D%20)
apply the data to formula
![pH = - log[H_{3} O^+]](https://tex.z-dn.net/?f=%20pH%20%3D%20-%20log%5BH_%7B3%7D%20O%5E%2B%5D%20)
![pH = - log[2.09*10^{-7}]](https://tex.z-dn.net/?f=%20pH%20%3D%20-%20log%5B2.09%2A10%5E%7B-7%7D%5D%20)



Note:. The pH <7, then we have an acidic solution (weak acid).
Now, let's find pOH by the following formula:




I Hope this helps, greetings ... DexteR! =)
Answer:
quantum mechanical model: A model of the atom that derives from the Schrödinger wave equation and deals with probabilities. wave function: Give only the probability of finding an electron at a given point around the nucleus. The quantum mechanical model of the atom also uses complex shapes of orbitals (sometimes called electron clouds), volumes of space in which there is likely to be an electron. So, this model is based on probability rather than certainty.
Answer:
Option 4 is correct (72 seconds)
Explanation:
Option 4 is correct (72 seconds)
The formula we are going to use is:

Where:
A is the final concentration
A_o is the initial concentration
k is the constant
t is the time
Half-Life=0.693/k
Half-life in our case=24 seconds
k=0.693/24
k=0.028875 s^-1
Since the concentration is decreased by 87.5 % which means only 12.5%(100-87.5%) is left.
The ratio
will become 0.125

t≅ 72 seconds
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Step 1:
Write molecular Formula,
Na₅P₃O₁₀
Step 2:
Assign Oxidation number to Na (which is +1) and O (which is -2), and X (unknown) for P.
(+1)₅ + (X)₃ + (-2)₁₀ = 0
Zero means overall charge on molecule is zero (Neutral).
Step 3:
Now solve for X,
(+5) + (X ÷ 3) + (-20) = 0
X ÷ 3 = -5 + 20
X ÷ 3 = +15
X = +15 ÷ 3
X = +5
Result:
Oxidation number of P is +5.