Oxidation is basically lose of electron..
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a)λ = 1.43 x 10⁻⁷ m, b)λ =5 x 10⁻¹⁹ and, c)λ = 1.99 x 10⁻⁷ m.
<h3>What is an atom?</h3>
- A chemical element is uniquely defined by its atoms, which are tiny pieces of substance. A core nucleus, often surrounded by one or more electrons, makes up an atom. The charge of every electron is negative. The positively charged nucleus has one or more protons and neutrons, relatively heavy particles.
- An atom is referred to any elementary particle of matter with at least one proton. Examples of atoms are neon (N) and hydrogen (H) (Ne).
- Protons, which have a positive charge, and neutrons, which have no charge, make up its structure. All regular, naturally occurring atoms contain the long-lived particles protons, neutrons, and the electrons that orbit them.
- It is difficult to appreciate how little they are until you see how many atoms there are in your body. Around 7 octillion atoms make up one adult.
a) The wavelength of the photon needed to excite an electron from E1 to E4:
ΔE = hc/λ
(-1 + 15) x 10⁻¹⁹ = 6.63 x 10⁻³⁴ x 3 x 10⁸ / λ
λ = 1.43 x 10⁻⁷ m
b) The energy (in joules) a photon must have in order to excite an electron from E2:
= (-5 + 10) x 10⁻¹⁹
λ = 5 x 10⁻¹⁹
c) An electron drops the E3 level to the E1 level, and the atom is said to undergo emission:
Change in energy = 10 x 10⁻¹⁹ J
10 x 10⁻¹⁹ = 6.63 x 10⁻³⁴ x 3 x 10⁸ / λ
λ = 1.99 x 10⁻⁷ m
The wavelength of the photon needed to excite an electron from E1 to E4 is 1.43 x 10⁻⁷ m.
The energy (in joules) a photon must have in order to excite an electron from E2 is 5 x 10⁻¹⁹.
An electron drops the E3 level to the E1 level, and the atom is said to undergo emission is 1.99 x 10⁻⁷ m.
To learn more about the hypothetical atom, refer to:
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Answer:
Highest boiling point - 0.43 m Urea
Second highest boiling point - 0.20 m NiSO4
Third highest boiling point - 0.19 m NH4I
Lowest boiling point - 0.17 m NH4NO3
Explanation:
We know that;
ΔT = kb m i
Where;
ΔT = boiling point elevation
kb = boiling point constant
m = molality of the solution
i = Van't Hoff factor
For NiSO4 , NH4I and NH4NO3 , the Van't Hoff factor, i = 2
But for Urea, the Van't Hoff factor, i = 1
We also have to consider both the values of the molality and Van't Hoff factor , knowing that a higher molality and a higher Van't Hoff factor leads to a higher ΔT and consequently a higher boiling point.
This facts above account for the arrangement of substances shown in the answer.
Answer:
Limiting reactant: Cl2.
Max mass of PCl3 = 41.44 g.
P4 leftover = 5.51 g.
Explanation:
Hello!
In this case, since the undergoing chemical reaction is:
In order to compute the maximum amount of PCl3, it is necessary to compute the grams of this product produced by each reactant, just as shown below, whereas molar masses and mole ratios are used:
Thus, since chlorine gas yields fewer grams of PCl3 than P4 we infer Cl2 is the limiting reactant and 63.41 grams of PCl3 product are yielded.
Finally, for the excess reactant, we see a difference of 63.41-41.44=21.97g, so we can compute of the leftover of P4 as follows:
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Answer:
There are 0.0528 moles of Chromium Carbonate (III) in 15 grams. See the explanation below, please.
Explanation:
We calculate the weight of 1 mol of compound having the atomic weights of each element.
Weight Cr = 51, 9961 g Weight 0 = 15, 999 Weight C =12, 0107
Weight of 1 mol of Cr2 (C03)3 =51, 9961 x2 + 3 x (12, 0107 + 15, 999x 3)=
284, 0342 g
284, 0342 g -----1 mol of Cr2 (C03)3
15 g -----X = (15g x 1 mol)/284, 0342 g = 0, 0528 mol