Answer:
0.45 miles
Explanation:
since, car will be running on the edge of track, distance covered in one lap by car will be equal to circumference of track.\
we will use value of pi as 22/7
Circumference for any circular shape is given by
Hence, in one lap distance will be covered
in 7 laps distance will be covered.
but is given that 7 laps should be equal to 10 miles
so 10 miles will be equal to
Thus, diameter of track will be 0.45 miles to meet the requirement.
Answer:
The volume of water that was in the kettle is 1170
Explanation:
Given:
Power, P = 2.0 kW = 2000 W, Mass of stainless steel, = 710 g = 0.71 kg at temperature of
Part A:
If it takes time, t = 3.5 minutes to reach boiling point of water , then from conservation of energy,
Total energy supplied by the burner = Total heat gained by the water and the stainless steel to rise from to
i.e. Pt = (100 - 20 ) +
(100 - 20 )
=
= 1.17 kg
where = 4200 J/Kgk (specific heat capacity of water),
= 450 J/Kgk (specific heat capacity of steel)
But volume of water in the the kettle, v =
∴ v = 1170