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VikaD [51]
4 years ago
7

If you see a rainbow near the time of sunset, where in the sky will the rainbow be?

Physics
1 answer:
Igoryamba4 years ago
8 0
Closest to the sun f thats a choice or closest to the atmoshpere
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Please help me eseghgtrhj
icang [17]

The correct answer is C.

3 0
3 years ago
Read 2 more answers
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Alborosie
Interesting question :)
8 0
4 years ago
Highlight two factors which show that heat from the sun does reach the earth surface by conversation
svetlana [45]

Answer:

Radiation

Explanation:

The sun heat the earth by the process called radiation.

Radiation is form of heat transfer method just like convection and conduction. Radiation heat transfer does not require medium to propagate, unlike its other two counterparts. There is no medium between earth and sun.

The radiation heat travels through space in form of waves. Like the electromagnetic wave with a specific speed and energy.

7 0
3 years ago
For the following types of electromagnetic radiation, how do the wavelength, frequency, and photon energy change as one goes fro
KIM [24]

Answer:

Wavelength, frequency and the photon energy changes as the one goes across the ranges of the electro-magnetic radiations.

Explanation:

Electro-magnetic radiations may be defined as the form of energy that is radiated or given by the electro-magnetic radiations. The visible light that we can see is the one of the electro-magnetic radiations. Other forms are the radio waves, gamma waves, UV rays, infrared radiations, etc.

The wavelength of the radiations decreases as we go from a. radio waves -- b. infrared radiation -- c. visible light -- d. ultraviolet radiation -- e. gamma radiation.

The frequency of the radiations increases when we move from a. radio waves -- b. infrared radiation -- c. visible light -- d. ultraviolet radiation -- e. gamma radiation.

The photon energy of the radiations increases when we move from a. radio waves -- b. infrared radiation -- c. visible light -- d. ultraviolet radiation -- e. gamma radiation.

5 0
3 years ago
A physics teacher is designing a ballistics event for a science competition. The ceiling is 3.00m high, and the maximum velocity
krek1111 [17]

The launch proyectiles of kinematics  allows to find the maximum initial vertical velocity of the body so that it just reaches the ceiling

             v_{oy} = 2.56 m / s

       

Given parameters

  • The ceiling height y = 3 m

To find

  • Maximum vertical speed

Projectile launching is an application of kinematics where on the x axis there is no acceleration or and on the y axis the acceleration is the acceleration of gravity (g = 9.8 m / s ^ 2)

In this case, the maximum vertical velocity that the body can have occurs when the velocity on the ceiling is zero.

            v_y² = v_{oy}² - 2 g y

where v and v_{oy} are the initial velocity at the ceiling e initial, respectively, g the acceleration of gravity e and the height

           0 = v_{oy}² - 2 g y

           v_{oy} = \sqrt{2gy}

           v_{oy} = \sqrt{2 \ 9.8 \ 3}

           v_{oy} = 2.56 m / s

In conclusion with the kinematic of launch projectiles we can find the maximum initial vertical velocity of the body so that it just reaches the ceiling

             v_{oy} = 2.56 m / s

learn more about projectile launch here:

brainly.com/question/10903823

3 0
3 years ago
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