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3 years ago

9

How do mutations affect natural selection.

1 answer:

mylen [45]3 years ago

5 0

Answer:

The answer is C.

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How many moles of potassium oxide (K2O) will be formed when 1.52 moles of potassium reacts with oxygen according to the followin

Ghella [55]

The balanced chemical reaction is given above however I believe the coefficients are wrong. It should be:

4K + O2 = 2K2O

We use data from that reaction to obtain relationships between substances. We are given the amount of potassium that reacts. We proceed as follows:

1.52 mol K ( 2 mol K2O / 4 mol K ) = 0.76 mol of K2O is formed

6 0

4 years ago

Any reaction that absorbs 150 kcal of energy can be classified as

Dennis_Churaev [7]

The answer should be (D) endothermic reaction.

Reason : - Reactions in which energy is absorbed are called endothermic reactions. In your provided question, 150 kcal energy is being <u>absorbed</u>, and thus, we can say that it is an endothermic reaction.

6 0

3 years ago

If you want to lift a 30-kg box to a height of 1 m, how much work will it take?

natta225 [31]

Explanation:

workdone = force x distance

force = mass x acceleration

30 x 10 = 300N

300N x 1m

workdone= 300J

7 0

3 years ago

When a metal was exposed to light at a frequency of 4.07× 1015 s–1, electrons were emitted with a kinetic energy of 3.30× 10–19

Licemer1 [7]

Answer : The maximum number of electrons released = $1.432\times 10^{12}electrons$

Explanation : Given,

Frequency = $4.07\times 10^{15}s^{-1}$

Kinetic energy = $3.30\times 10^{-19}J$

Total energy = $3.39\times 10^{-7}J$

First we have to calculate the work function of the metal.

Formula used :

$K.E=h\nu -w$

where,

K.E = kinetic energy

h = Planck's constant = $6.626\times 10^{-34}J/s$

$\nu$ = frequency

w = work function

Now put all the given values in this formula, we get the work function of the metal.

$3.30\times 10^{-19}J=(6.626\times 10^{-34}J/s\times 4.07\times 10^{15}s^{-1})-w$

By rearranging the terms, we get

$w=2.367\times 10^{-18}J$

Therefore, the works function of the metal is, $2.367\times 10^{-18}J$

Now we have to calculate the maximum number of electrons released.

The maximum number of electrons released = $\frac{\text{ Total energy}}{\text{ work function}}$

The maximum number of electrons released = $\frac{3.39\times 10^{-7}J}{2.367\times 10^{-19}J}=1.432\times 10^{12}electrons$

Therefore, the maximum number of electrons released is $1.432\times 10^{12}electrons$

8 0

3 years ago

What formula do you use to calculated density?

Aleks [24]

Answer:

7 AM was the first to be the best Friend and a friend and I have seen the target market share of a million dollars and Diamond.

8 0

3 years ago

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