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iogann1982 [59]
3 years ago
5

Imagine that you have a rectangular swimming pool, but you have no idea how deep it is. You

Chemistry
1 answer:
Ann [662]3 years ago
7 0
To calculate the volume of any rectangular shape,
We can simply multiply length to wide and to depth.
Let d be the depth.
15 x 6 x d = 216
d = 216 / 15 / 6
d = 2.4
Therefore the depth is 2.4m
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A gas that exerts a pressure of 537 torr in a container with a volume of 5.30 L will exert a pressure of 255 torr when transferr
ArbitrLikvidat [17]

Answer:- The gas needs to be transferred to a container with a volume of 11.2 L.

Solution:- From Boyle's law. "At constant temperature, Volume is inversely proportional to the pressure."

It means, the volume is decreased if the pressure is increased and vice versa.

Here, the Pressure is decreasing from 537 torr to 255 torr. So, the volume must increase and calculated by using the equation:

P_1V_1=P_2V_2

Where, P_1 is initial pressure and P_2 is final pressure. Similarly, V_1 is initial volume and V_2 is final volume.

Let's plug in the values in the equation:

(537 torr)(5.30 L) = (255 torr)(V_2)

V_2=(\frac{537 torr*5.30 L}{255 torr})

V_2 = 11.2 L

So, the new volume of the container needs to be 11.2 L.

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3 years ago
Which of the following is a product of photosynthesis reaction
SpyIntel [72]
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When matter is broken down physically by wind or chemically by salt water, what is this known as?
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How many grams of oxygen gas are contained in a 15 L sample at 1.02 atm and 28°C? Please show your work.
vampirchik [111]

Answer:

0.019 g.

Explanation:

  • Firstly, we need to find the no. of moles of oxygen gas:
  • We can use the general law of ideal gas: <em>PV = nRT. </em>

where, P is the pressure of the gas in atm (P = 1.02 atm).

V is the volume of the gas in L (V = 15.0 L).

n is the no. of moles of the gas in mol (n = ??? mol).

R is the general gas constant (R = 0.0821 L.atm/mol.K),

T is the temperature of the gas in K (T = 28°C + 273 = 301.0 K).

∴ n = PV/RT = (1.02 atm)(15.0 L)/(0.0821 L.atm/mol.K)(301.0 K) = 0.62 mol.

  • To find the mass of oxygen gas, we have:

<em>no. of moles = mass/molar mass.</em>

<em></em>

∴ mass of oxygen = (no. of moles)(molar mass) = (0.62 mol)(32.0 g/mol) = 0.019 g.

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How to add magnisume and chloride togather
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Magnesium plus chlorine equals to magnesium chloride
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