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viva [34]
3 years ago
10

When the pressure of a gas sample is decreased what happens to the volume?

Chemistry
2 answers:
solniwko [45]3 years ago
6 0
The combined gas<span> law states that the </span>pressure of a gas<span> is inversely related to the</span>volume<span> and directly related to the </span>temperature<span>. If </span>temperature<span> is held constant, the equation is </span>reduced<span> to Boyle's law. Therefore, if you </span>decrease<span> the </span>pressure<span> of a fixed amount of </span>gas<span>, its </span>volume<span> will increase.</span>
tiny-mole [99]3 years ago
4 0
The amount of volume will increase <span />
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complete the name of an alkali that could react with phosphoric acid to make sodium hydrogen phosphate
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The answer is sodium hydroxide
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You have a solution of calcium chloride dissolved in water. You add some more solid to the solution and stir, and the solid diss
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Answer:

It changed from unsaturated to saturated solution

Explanation:

Before adding the spatula tip full amount, the solution was unsaturated, but as soon as the spatula tip full amount was added and couldn't dissolve, it became unsaturated because it could not dissolve any more solute having already dissolved it maximum number of solute

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3 years ago
If a lab requires each a lab group (3 students) to have 25 ml of a solution and it takes 15 grams of AgNO₃ cuprous nitrate, to m
pochemuha

Answer:

0.375 grams are needed to make 25 mL solution.

Explanation:

Mass of AgNO_3 cuprous nitrate required to make 1 l of solution = 15 g.

1 L = 1000 mL

Mass of AgNO_3 cuprous nitrate required to make 1000 mL of solution = 15 g

Mass of AgNO_3 cuprous nitrate required to make 1 mL of solution:

=\frac{15}{1000} g

Mass of AgNO_3 cuprous nitrate required to make 25 mL of solution:

=\frac{15}{1000} \times 25 g=0.375 g

0.375 grams are needed to make 25 mL solution.

4 0
3 years ago
A balloon of hydrogen is subjected to vacuum. The initial pressure and volume of hydrogen is 0.95 atm and 0.55 L. Calculate the
Scilla [17]

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0.43 atm

Explanation:

From the question given above, the following data were obtained:

Initial pressure (P₁) = 0.95 atm

Initial volume (V₁) = 0.55 L

Final volume (V₂) = 1.22 L

Final pressure (P₂) =?

The final pressure of the gas can be obtained by using the Boyle's law equation as follow:

P₁V₁ = P₂V₂

0.95 × 0.55 = P₂ × 1.22

0.5225 = P₂ × 1.22

Divide both side by 1.22

P₂ = 0.5225 / 1.22

P₂ = 0.43 atm

Therefore, the final pressure of the gas is 0.43 atm

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The correct answer is A
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