**Answer:**

y = L h / a √√ (2q V m)

**Explanation:**

This is a diffraction exercise, so we must use the D'Broglie relation to encode the wavelength of the electron beam.

p = h / λ

λ= h / p

the moment is

p = m v

λ = h / mv

Let's use energy conservation

E = K

q ΔV = ½ m v²

v = √ 2qΔv / m

λ = h / (m √2q ΔV / m)

λ = h / √ (2q ΔV m)

Having the wavelength of the electrons we can use the diffraction ratio

a sin θ = m λ

First minimum occurs for m = 1

sin θ = λ / a

let's use trigonometry for the angles

tan θ = y / x

as in these experiments the angles are very small

tan θ = sin θ / cos θ = sin θ

sin θ = y / x

we substitute

y / x = λ / a

y = x λ / a

we replace the terms

y = L h / a √√ (2q V m)

The formula for finding the frequency of a wave is with the following formula:

F = 1/T, F being the variable for frequency and T substituting as time. Given we already have our time, let's plug it in for T.

F = 1/4. This means our answer is in some mathematical form that is equivalent to 1/4. We have the answer "**0.25 waves/second**", which is equivalent to our original fraction (0.25 x 4 = 1.00).

I hope this helps!

**Answer with Explanation:**

We are given that

r=3 m

Angular frequency==560rev/min

A.1 revolution= radian

560 revolutions= rad

Angular frequency=rad/s

**1 min=60 s**

Angular frequency=

Linear speed=

Using the formula

Linear speed=

**Hence, the linear speed of the blade tip=175.8m/s**

B.**Radial acceleration=**

By using the formula

Radial acceleration=

Radial acceleration=

Where** **

**Hence, the radial acceleration**

A object that has been reinvented so it is more energy efficient