Answer: the answer for the question is a
Explanation:
Answer:
the pressure reading when connected a pressure gauge is 543.44 kPa
Explanation:
Given data
tank volume (V) = 400 L i.e 0.4 m³
temperature (T) = 25°C i.e. 25°C + 273 = 298 K
air mass (m) = 3 kg
atmospheric pressure = 98 kPa
To find out
pressure reading
Solution
we have find out pressure reading by gauge pressure
i.e. gauge pressure = absolute pressure - atmospheric pressure
first we find absolute pressure (p) by the ideal gas condition
i.e pV = mRT
p = mRT / V
p = ( 3 × 0.287 × 298 ) / 0.4
p = 641.44 kPa
so
gauge pressure = absolute pressure - atmospheric pressure
gauge pressure = 641.44 - 98
gauge pressure = 543.44 kPa
Translate- What is the influence of a leader in the business sector and as reflected
In the company or business?
Answer:
mV
Explanation:
The voltage across a capacitor at a time t, is given by:
----------------(i)
Where;
v(t) = voltage at time t
= initial time
C = capacitance of the capacitor
i(t) = current through the capacitor at time t
v(t₀) = voltage at initial time.
From the question:
C = 2μF = 2 x 10⁻⁶F
i(t) = 3 mA
t₀ = 0
v(t₀ = 0) = 0
Substitute these values into equation (i) as follows;
[Solve the integral]
Therefore, the voltage across the capacitor is mV