Answer:
The mass flow rate of the mixture in the manifold is 6.654 kg/min
Explanation;
In this question, we are asked to calculate mass flow rate of the mixture in the manifold
Please check attachment for complete solution and step by step explanation.
Answer:
C). rearview mirror (at least of four inches by four inches).
Explanation:
<u>A 'rearview mirror' would be needed in case one is required to pull an individual on water skis after a PWC(personal watercraft) that is rated for carrying two persons only</u>. This wide-angle mirror for rearview would allow the operator to monitor the person who is being towed constantly along with riding the ski at the same time. It is considered illegal to tow a person on a vessel without having a rearview mirror and at the same time, the limited capacity must also be followed strictly. Hence, <u>option C</u> is the correct answer.
Answer:
I don't know ask my dad he would
Explanation:
but I can't ask him because he went to get milk and forgot to come back
Answer:
(a) 11.437 psia
(b) 13.963 psia
Explanation:
The pressure exerted by a fluid can be estimated by multiplying the density of the fluid, acceleration due to gravity and the depth of the fluid. To determine the fluid density, we have:
fluid density = specific gravity * density of water = 1.25 * 62.4 lbm/ft^3 = 78 lbm/ft^3
height = 28 in * (1 ft/12 in) = 2.33 ft
acceleration due to gravity = 32.174 ft/s^2
The change in pressure = fluid density*acceleration due to gravity*height = 78*32.174*(28/12) = 5855.668 lbm*ft/(s^2 * ft^2) = 5855.668 lbf/ft^2
The we convert from lbf/ft^2 to psi:
(5855.668/32.174)*0.00694 psi = 1.263 psi
(a) pressure = atmospheric pressure - change in pressure = 12.7 - 1.263 = 11.437 psia
(b) pressure = atmospheric pressure + change in pressure = 12.7 + 1.263 = 13.963 psia
Answer:
a)
, b)
, c)
, d) ![t = 40.588\,years](https://tex.z-dn.net/?f=t%20%3D%2040.588%5C%2Cyears)
Explanation:
a) The area of the solar panel is:
![A = (20\,ft^{2})\cdot (\frac{0.3048\,m}{1\,ft} )^{2}](https://tex.z-dn.net/?f=A%20%3D%20%2820%5C%2Cft%5E%7B2%7D%29%5Ccdot%20%28%5Cfrac%7B0.3048%5C%2Cm%7D%7B1%5C%2Cft%7D%20%29%5E%7B2%7D)
![A = 1.858\,m^{2}](https://tex.z-dn.net/?f=A%20%3D%201.858%5C%2Cm%5E%7B2%7D)
The energy potential is determined herein:
![\dot E_{o} = (1000\,\frac{W}{m^{2}} )\cdot (1.858\,m^{2})](https://tex.z-dn.net/?f=%5Cdot%20E_%7Bo%7D%20%3D%20%281000%5C%2C%5Cfrac%7BW%7D%7Bm%5E%7B2%7D%7D%20%29%5Ccdot%20%281.858%5C%2Cm%5E%7B2%7D%29)
![\dot E_{o} = 1858\,W](https://tex.z-dn.net/?f=%5Cdot%20E_%7Bo%7D%20%3D%201858%5C%2CW)
The efficiency of the solar panel is:
![\eta = \frac{\dot E}{\dot E_{o}}\times 100\%](https://tex.z-dn.net/?f=%5Ceta%20%3D%20%5Cfrac%7B%5Cdot%20E%7D%7B%5Cdot%20E_%7Bo%7D%7D%5Ctimes%20100%5C%25)
![\eta = \frac{250\,W}{1858\,W}\times 100\%](https://tex.z-dn.net/?f=%5Ceta%20%3D%20%5Cfrac%7B250%5C%2CW%7D%7B1858%5C%2CW%7D%5Ctimes%20100%5C%25)
![\eta = 13.455\%](https://tex.z-dn.net/?f=%5Ceta%20%3D%2013.455%5C%25)
b) The energy generated by the solar panel is presented below:
![E_{day} = (0.135)\cdot (150\,\frac{W}{m^{2}} )\cdot (20\,ft^{2})\cdot \left(\frac{0.3048\,m}{1\,ft} \right)^{2}\cdot (6\,h)\cdot (\frac{3600\,s}{1\,h} )\cdot (\frac{1\,kJ}{1000\,J} )](https://tex.z-dn.net/?f=E_%7Bday%7D%20%3D%20%280.135%29%5Ccdot%20%28150%5C%2C%5Cfrac%7BW%7D%7Bm%5E%7B2%7D%7D%20%29%5Ccdot%20%2820%5C%2Cft%5E%7B2%7D%29%5Ccdot%20%5Cleft%28%5Cfrac%7B0.3048%5C%2Cm%7D%7B1%5C%2Cft%7D%20%5Cright%29%5E%7B2%7D%5Ccdot%20%286%5C%2Ch%29%5Ccdot%20%28%5Cfrac%7B3600%5C%2Cs%7D%7B1%5C%2Ch%7D%20%29%5Ccdot%20%28%5Cfrac%7B1%5C%2CkJ%7D%7B1000%5C%2CJ%7D%20%29)
![E_{day} = 812.716\,kJ](https://tex.z-dn.net/?f=E_%7Bday%7D%20%3D%20812.716%5C%2CkJ)
c) The energy generated per month and per panel is:
![E_{month} = 30\cdot E_{day}](https://tex.z-dn.net/?f=E_%7Bmonth%7D%20%3D%2030%5Ccdot%20E_%7Bday%7D)
![E_{month} = 30 \cdot (812.716\,kJ)\cdot \left(\frac{1\,kWh}{3600\,kJ} \right)](https://tex.z-dn.net/?f=E_%7Bmonth%7D%20%3D%2030%20%5Ccdot%20%28812.716%5C%2CkJ%29%5Ccdot%20%5Cleft%28%5Cfrac%7B1%5C%2CkWh%7D%7B3600%5C%2CkJ%7D%20%20%5Cright%29)
![E_{month} = 6.773\,kWh](https://tex.z-dn.net/?f=E_%7Bmonth%7D%20%3D%206.773%5C%2CkWh)
Monthly energy savings due to the use of 18 panels are:
![C_{month, total} = 18\cdot E_{month}\cdot c](https://tex.z-dn.net/?f=C_%7Bmonth%2C%20total%7D%20%3D%2018%5Ccdot%20E_%7Bmonth%7D%5Ccdot%20c)
![C_{month, total} = 18\cdot (6.773\,kWh)\cdot (\frac{0.16\,USD}{1\,kWh} )](https://tex.z-dn.net/?f=C_%7Bmonth%2C%20total%7D%20%3D%2018%5Ccdot%20%286.773%5C%2CkWh%29%5Ccdot%20%28%5Cfrac%7B0.16%5C%2CUSD%7D%7B1%5C%2CkWh%7D%20%29)
![C_{month. total} = 19.505\, USD](https://tex.z-dn.net/?f=C_%7Bmonth.%20total%7D%20%3D%2019.505%5C%2C%20USD)
d) The payback of the solar energy system is:
![t = \frac{9500\,USD}{12\cdot (19.505\,USD)}](https://tex.z-dn.net/?f=t%20%3D%20%5Cfrac%7B9500%5C%2CUSD%7D%7B12%5Ccdot%20%2819.505%5C%2CUSD%29%7D)
![t = 40.588\,years](https://tex.z-dn.net/?f=t%20%3D%2040.588%5C%2Cyears)