In your opinion...

11. Which of these is NOT true when dealing with refrigerants?

Alexus [3.1K]

Answer is an increase in pressure will cause an decrease in the pressure

4 0

3 years ago

Need help solving math problem using integration

notka56 [123]

Ummm did you try to add or subtract and multiply or divide that can get your answer

8 0

2 years ago

Two thousand pieces will flow through from the first machine A to the final machine F based on the given sequence of operations.

Vlad1618 [11]

The total number of trips that the vehicle has to make based on the given sequence of operation is 120 trips.

"Your question is not complete, it seems to be missing the following information;"

The sequence of operation is A - E - D - C - B - A - F

The given parameters;

number of pieces that will flow from the first machine A to machine F, = 2,000 pieces
initial unit load specified in the first machine, L₁ = 50
final unit load, L₂ = 100
the capacity of the vehicle = 1 unit load

The given sequence of operation of the vehicle;

A - E - D - C - B - A - F

the vehicle makes 6 trips for 100 unit loads

The total number of trips that the vehicle has to make, in order to transport the 2000 pieces of the load given, is calculated as follows.

100 unit loads ----------------- 6 trips

2000 unit loads --------------- ?

$= \frac{2000}{100} \times 6\\\\= 120 \ trips$

Thus, the total number of trips that the vehicle has to make based on the given sequence of operation is 120 trips.

Learn more here:brainly.com/question/21468592

6 0

2 years ago

A plate clutch has a single friction surface 9-in OD by 7-in ID. The coefficient of friction is 0.2 and the maximum pressure is

Talja [164]

Answer:

the torque capacity is 30316.369 lb-in

Explanation:

Given data

OD = 9 in

ID = 7 in

coefficient of friction = 0.2

maximum pressure = 1.5 in-kip = 1500 lb

To find out

the torque capacity using the uniform-pressure assumption.

Solution

We know the the torque formula for uniform pressure theory is

torque = 2/3 × $\pi$ × coefficient of friction × maximum pressure ( R³ - r³ ) .....................................1

here R = OD/2 = 4.5 in and r = ID/2 = 3.5 in

now put all these value R, r, coefficient of friction and maximum pressure in equation 1 and we will get here torque

torque = 2/3 × $\pi$ × 0.2 × 1500 ( 4.5³ - 3.5³ )

so the torque = 30316.369 lb-in

3 0

3 years ago

The heat required to raise the temperature of m (kg) of a liquid from T1 to T2 at constant pressure is Z T2CpT dT (1) In high sc

a_sh-v [17]

Answer:

(a)

dQ = mdq

dq = $C_p$ dT

$q = \int\limits^{T_2}_{T_1} {C_p} \, dT$ = $C_p$ (T₂ - T₁)

From the above equations, the underlying assumption is that $C_p$ remains constant with change in temperature.

(b)

Given;

V = 2L

T₁ = 300 K

Q₁ = 16.73 KJ , Q₂ = 6.14 KJ

ΔT = 3.10 K , ΔT₂ = 3.10 K for calorimeter

Let $C_{cal}$ be heat constant of calorimeter

Q₂ = $C_{cal}$ ΔT

Heat absorbed by n-C₆H₁₄ = Q₁ - Q₂

Q₁ - Q₂ = m $C_p$ ΔT

number of moles of n-C₆H₁₄, n = m/M

ρ = 650 kg/m³ at 300 K

M = 86.178 g/mol

m = ρv = 650 (2x10⁻³) = 1.3 kg

n = m/M => 1.3 / 0.086178 = 15.085 moles

Q₁ - Q₂ = m $C_p$ ' ΔT

$C_p$ = (16.73 - 6.14) / (15.085 x 3.10)

$C_p$ = 0.22646 KJ mol⁻¹ k⁻¹

6 0

3 years ago