Weak winds that blow for short periods of time with a short fetch.
Answer: The molar heat capacity of aluminum is 
Explanation:
As we know that,
![m_1\times c_1\times (T_{final}-T_1)=-[m_2\times c_2\times (T_{final}-T_2)]](https://tex.z-dn.net/?f=m_1%5Ctimes%20c_1%5Ctimes%20%28T_%7Bfinal%7D-T_1%29%3D-%5Bm_2%5Ctimes%20c_2%5Ctimes%20%28T_%7Bfinal%7D-T_2%29%5D)
.................(1)
where,
q = heat absorbed or released
= mass of water = 130.0 g
= mass of aluminiunm = 23.5 g
= final temperature
= 
= temperature of water = 
= temperature of aluminium = 
= specific heat of water= 
= specific heat of aluminium= ?
Now put all the given values in equation (1), we get
![130.0\times 4.184\times (299-296)=-[23.5\times c_2\times (299-373)]](https://tex.z-dn.net/?f=130.0%5Ctimes%204.184%5Ctimes%20%28299-296%29%3D-%5B23.5%5Ctimes%20c_2%5Ctimes%20%28299-373%29%5D)
Molar mass of Aluminium = 27 g/mol
Thus molar heat capacity =
It traveled 200 m in 50 seconds. 200/50 can be simplified to 4 m/s!
The velocity is -4 m/s (negative because it travelled from 100 to -100 or backwards)
We are given the gravitational potential energy and the height of the ball and is asked in the problem to determine the mass of the ball. the formula to be followed is PE = mgh where g is the gravitational acceleration equal to 9.81 m/s^2. substituting, 58.8 J = m*9.8 m/s^2 * 30 m; m = 0.2 kg.
