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4 years ago

Dome mountains are formed when:

Chemistry

1 answer:

Airida [17]4 years ago

6 0

Answer:

Dome mountains are formed when hot molten material (magma) rising from the Earth's mantle into the crust that pushes overlying sedimentary rock layers upward to form a “dome” shape.

Explanation:

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2FeCl3 + MgO -> Fe2O3 + 3MgCl2<br> Convert 3.00 moles of MgO to moles of Fe2O3

nikitadnepr [17]

71.8 g of iron (III) oxide (Fe₂O₃) were produced from 3 moles of magnesium oxide (MgO).

Explanation:

We have the following chemical reaction:

2 FeCl₃ + 3 MgO → Fe₂O₃ + 3 MgCl₂

We see from the chemical reaction that 3 moles of magnesium oxide (MgO) will produce 1 mole of iron (III) oxide (Fe₂O₃).

number of moles = mass / molar weight

mass = number of moles × molar weight

mass of Fe₂O₃ = 1 × 71.8 = 71.8 g

Learn more about:

number of moles

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6 0

3 years ago

Which non-metal or metalloid is the most reactive?

Neko [114]

C. Borin is the answer

4 0

3 years ago

Read 2 more answers

HELP!!!!

ale4655 [162]

Answer: Option (b) is the correct answer.

Explanation:

Since energy of reactants is less than the energy of products. Therefore, it means energy is absorbed during the reaction.

As the energy required to break the bonds in the reactants is greater than the energy released when products are formed.

Therefore, it is an endothermic reaction.

Thus, we can conclude that the statement, it is endothermic because the energy required to break bonds in the reactants is greater than the energy released when the products are formed is correct.

5 0

3 years ago

Read 2 more answers

Balance the equation.<br>P + 02 --> P4O10

charle [14.2K]

Answer:

4P + 5O₂ —> P₄O₁₀

Explanation:

From the question given above, we obtained:

P + O₂ —> P₄O₁₀

The above equation can be balance as illustrated below:

P + O₂ —> P₄O₁₀

There are 4 atoms of P on the right side and 1 atom on the left side. It can be balance by 4 in front of P as shown below:

4P + O₂ —> P₄O₁₀

There are 10 atoms of O on the right side and 2 atoms on the left side. It can be balance by putting 5 in front of O₂ as shown below:

4P + 5O₂ —> P₄O₁₀

Now the equation is balanced.

6 0

3 years ago

Some SO2 and O2 are mixed together in a flask at 1100 K in such a way ,that at the instant of mixing, their partial pressures ar

kakasveta [241]

Answer:

The answer is " $\bold{0.525\ \ atm^{-1}}$ "

Explanation:

Given equation:

$2SO_2(g) + O_2(g) \leftrightharpoons 2SO_3(g)$

Given value:

$\Delta rH =-198.2 \ \ \frac{KJ}{mol}$

$Kp=1100 \ K$

$\Delta x = 2-(2+1)\\\\$

$= 2-(2+1)\\\\= 2-(3)\\\\= -1$

$\left\begin{array}{cccc}I\ (atm)&1&0.5&0\\C\ (atm)&2x&-x&2x\\E\ (atm) &1-2x&0.5-x&2x\end{array}\right$

calculating the total pressure on equilibrium= $(1-2x)+(0.5-x)+2x \ atm\\\\$

$= 1-2x+0.5-x+2x\\\\= 1+0.5-x\\\\=1.5-x\\$

$\therefore \\\\\to 1.50-x= 1.35 \\\\\to 1.50-1.35= x\\\\\to 0.15= x\\\\ \to x= 0.15\\\\$

calculating the pressure in $So_2$ :

$= (1-2 \times 0.15)$

$= 1-0.30 \\\\ =0.70 \ atm$

calculating the pressure in $O_2$ :

$= (0.5- 0.15)\\\\= 0.35 \ atm \\$

calculating the pressure in $So_3$ :

$= (2 \times 0.15)\\\\= (.30) \ atm \\\\$

Calculating the Kp at 1100 K:

$= \frac{(Pressure(So_3))^2}{(Pressure(So_2))^2 \times Pressure(O_2)}\\\\= \frac{0.30^2}{0.70^2 \times 0.35}\\\\= \frac{0.30 \times 0.30 }{0.70\times 0.70 \times 0.35}\\\\= \frac{0.09 }{0.49\times 0.35} \\\\= \frac{0.09 }{0.1715} \\\\= 0.5247 \ \ or \ \ 0.525 \ \ atm^{-1} \\\\$

4 0

3 years ago