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2 years ago

How many grams of water contain 2.50 x 10^24 atoms of hydrogen?

Chemistry

1 answer:

Mama L [17]2 years ago

4 0

The mass of water that contains 2.5×10²⁴ atoms of Hydrogen is 74.79 g

<h3>Avogadro's hypothesis </h3>

From Avogadro's hypothesis,

6.02×10²³ atoms = 2 g of H

Therefore,

2.5×10²⁴ atoms = (2.5×10²⁴ × 2) / 6.02×10²³

2.5×10²⁴ atoms = 8.31 g of H

<h3>How to determine the mass of water </h3>

1 mole of water H₂O = (2×1) + 16 = 18 g
Mass of H in 1 mole of water = 2 g

2 g of H is present in 18 g of water.

Therefore,

8.31 g of H will be present in = (8.31 × 18) / 2 = 74.79 g of water.

Thus, 2.5×10²⁴ atoms of Hydrogen is present in 74.79 g of water.

Learn more about Avogadro's number:

brainly.com/question/26141731

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How many formula units are contained in 23.5 g of Sb2S3

wolverine [178]

The molar mass of Sb2S3 is approximately equal to 339.7 g/mol. We calculate the number of moles of Sb2S3 by dividing the given mass by the molar mass.
n = 23.5 g / (339.7 g/mol)
n = 0.0692 mols
To calculate for the number of formula units, we multiply the number of mols by the Avogadro's number,
number of formula units = (0.0692 mols)(6.022 x 10^3)
= 4.167 x 10^22 formula units

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3 years ago

Read 2 more answers

A student needed to make 100.0 mL of 0.20M NaOH solution. How many grams of sodium hydroxide does the student need to weigh out

GuDViN [60]

Answer:

0.08 g

Explanation:

100.0 mL = 0.10 L

Multiply the volume by the molarity to find moles.

0.10 L × 0.20 M = 0.002 mol

Convert moles to grams.

0.002 mol × 40 g/mol = 0.08 g

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3 years ago

How many molecules of nh3 could be made from 10 molecules of n2 and 30 molecules of h2?

lorasvet [3.4K]

You can make 10 because that is the most N2 you have. The first one that runs out limits further molecules to be made

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3 years ago

An iron(iii) sulfate hydrate is 18.4% water. What is the formula of the hydrate? What is the name of the hydrate?

aleksley [76]

Answer:- Formula of the hydrate is $Fe_2(SO_4)_3.5H_2O$ and it's name is Iron(III)sulfate pentahydrate.

Solution:- As per the given information, there is 18.4% water in the hydrate. If we assume the mass of the hydrate as 100 grams then there would be 18.4 grams of water and 81.6 grams of Iron(III)sulfate present in the hydrate.

Molar mass for Iron(III)sulfate is 399.88 gram per mol and the molar mass for water is 18.02 gram per mol.

We will calculate the moles of Iron(III)sulfate and water present in the compound on dividing their grams by their molar masses as:

$81.6gFe_2(SO_4)_3(\frac{1mol}{399.88g})$

= $0.204molFe_2(SO_4)_3$

$18.4gH_2O(\frac{1mol}{18.02g})$

= $1.02molH_2O$

Now, the next step is to calculate the mol ratio and for this we divide the moles of each by the least one of them means whose moles are less. Here, the moles of Iron(III)sulfate are less than moles of water. So, we divide the moles of each by 0.204.

$Fe_2(SO_4)_3=\frac{0.204}{0.204}$ = 1

$H_2O=\frac{1.02}{0.204}$ = 5

There is 1:5 mol ratio between Iron(III)sulfate and water. So, the formula of the hydrate is $Fe_2(SO_4)_3.5H_2O$ and the name of the hydrate is Iron(III)sulfate pentahydrate.

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Oksana_A [137]

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