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Andreyy89
2 years ago
7

How many grams of water contain 2.50 x 10^24 atoms of hydrogen?

Chemistry
1 answer:
Mama L [17]2 years ago
4 0

The mass of water that contains 2.5×10²⁴ atoms of Hydrogen is 74.79 g

<h3>Avogadro's hypothesis </h3>

From Avogadro's hypothesis,

6.02×10²³ atoms = 2 g of H

Therefore,

2.5×10²⁴ atoms = (2.5×10²⁴ × 2) / 6.02×10²³

2.5×10²⁴ atoms = 8.31 g of H

<h3>How to determine the mass of water </h3>
  • 1 mole of water H₂O = (2×1) + 16 = 18 g
  • Mass of H in 1 mole of water = 2 g

2 g of H is present in 18 g of water.

Therefore,

8.31 g of H will be present in = (8.31 × 18) / 2 = 74.79 g of water.

Thus, 2.5×10²⁴ atoms of Hydrogen is present in 74.79 g of water.

Learn more about Avogadro's number:

brainly.com/question/26141731

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Calculate the hydronium ion concentration in an aqueous solution with a poh of 4.33 at 25°c.
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Taking into account the definition of pH and pOH, the hydronium ion concentration in an aqueous solution with a pOH of 4.33 at 25°c is 2.138×10⁻¹⁰ M.

<h3>Definition of pH</h3>

pH is a measure of acidity or alkalinity that indicates the amount of hydrogen ions present in a solution or substance.

The pH is defined as the negative base 10 logarithm of the activity of hydrogen ions, that is, the concentration of hydrogen ions or  hydronium ion H₃O⁺:

pH= - log [H⁺]= - log [H₃O⁺]

<h3>Definition of pOH</h3>

Similarly, pOH is a measure of hydroxyl ions in a solution and is expressed as the logarithm of the concentration of OH⁻ ions, with the sign changed:

pOH= - log [OH⁻]

<h3>Relationship between pH and pOH</h3>

The following relationship can be established between pH and pOH:

pOH + pH= 14

<h3>Concentration of hydronium ions</h3>

Being pOH= 4.33, pH is calculated as:

pH + 4.33= 14

pH= 14 - 4.33

<u><em>pH= 9.67</em></u>

Replacing in the definition of pH the concentration of hydronium ions is obtained:

- log [H₃O⁺]= 9.67

Solving:

[H₃O⁺]= 10⁻⁹ ⁶⁷

<u><em>[H₃O⁺]= 2.138×10⁻¹⁰ M</em></u>

Finally, the hydronium ion concentration in an aqueous solution with a pOH of 4.33 at 25°c is 2.138×10⁻¹⁰ M.

Learn more about pH and pOH:

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