Question

How many grams of water contain 2.50 x 10^24 atoms of hydrogen?

Answer 1

The mass of water that contains 2.5×10²⁴ atoms of Hydrogen is 74.79 g

Avogadro's hypothesis

From Avogadro's hypothesis,

6.02×10²³ atoms = 2 g of H

Therefore,

2.5×10²⁴ atoms = (2.5×10²⁴ × 2) / 6.02×10²³

2.5×10²⁴ atoms = 8.31 g of H

How to determine the mass of water

• 1 mole of water H₂O = (2×1) + 16 = 18 g
• Mass of H in 1 mole of water = 2 g

2 g of H is present in 18 g of water.

Therefore,

8.31 g of H will be present in = (8.31 × 18) / 2 = 74.79 g of water.

Thus, 2.5×10²⁴ atoms of Hydrogen is present in 74.79 g of water.

Learn more about Avogadro's number:

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