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2 years ago

Choose a system consisting only of ball A. What is the momentum change of the system during the collision?

Physics

1 answer:

shusha [124]2 years ago

3 0

The momentum change of the system during the collision is always equals to one another.

<h3>Momentum change during collision</h3>

In a collision, the momentum change of first object is equal to and opposite of the momentum change of second object with which the first one collided. Or in other words, the momentum lost by first object is equal to the momentum gained by second object.

The total momentum of the system means the collection of two objects is conserved so we can conclude that the momentum change of the system during the collision is always equals and opposite to one another.

Learn more about collisions here: brainly.com/question/7538238

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A racetrack has the shape of an inverted cone, as the drawing shows. On this surface the cars race in circles that are parallel

sergey [27]

Answer:

The value of d is 183.51 m.

Explanation:

Given that,

Speed of car = 34.0 m/s

Suppose The car race in the circle parallel to the ground surface is at an angle 40°

The radius of circular path $r = d\cos\theta$

Normal force acting on the car = N

We need to calculate the value of d

Using component of normal force

The horizontal component of normal force is equal to the gravitational force.

$N\cos\theta=mg$ ....(I)

The vertical component of normal force is equal to the centripetal force

$N\sin\theta=\dfrac{mv^2}{r}$ .....(II)

Divided equation (I) by equation (II)

$\tan\theta=\dfrac{v^2}{gr}$

Put the value of g

$\tan\theta=\dfrac{v^2}{g\times d\cos\theta}$

$v^2=\tan\theta\times g\times d\cos\theta$

$v^2=g\times d\sin\theta$

$d=\dfrac{v^2}{g\sin\theta}$

Put the value into the formula

$d=\dfrac{(34.0)^2}{9.8\times\sin40}$

$d=183.51\ m$

Hence, The value of d is 183.51 m.

3 0

3 years ago

Can someone explain it with steps?

Anton [14]

Answer:

Option C is the correct answer

Explanation:

Distance travelled by car during reaction time

$=15\times0.4\\\\=6m$

The car stopped before hitting the animal by $1 m$

Distance travelled during deceleration is $21-6-1=14m$

Hence by $v^2=u^2+2as$

We have

$0^2=15^2+2 \cdot a \cdot 14\\\\a=\frac{-225}{28} \\\\=-8.03m/s^2$

Option C is the correct answer

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2 years ago

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Answer:

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Explanation:

i think i hope this helps

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DiKsa [7]

Answer:

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