The answer is 166 mL. You use the formula V1*M1=V2*M2. For what you're given you rearrange the formula to V1=M2*V2/M1 so V1= (0.500 mL)(0.100 M AgNO3)/(0.300 M AgNO3) = 166 mL
Sorry bro but idk maybe its :1 L=<span>103</span><span>mL</span>
I think the answer is D. Contains nitrogen bases hope it helps.
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