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Nina [5.8K]
2 years ago
11

AT constant temperature, a gas is compressed from 5.5 L to 1 L. At 1 L, the pressure of the gas is 98.2 kPa. What was the origin

al pressure of this gas? (Use Boyle's Law)
Chemistry
1 answer:
svet-max [94.6K]2 years ago
7 0

We have that  the original pressure of this gas  is mathematically given as

P2=17.854 kPa

<h3>Boyle's law</h3>

Question Parameters:

AT constant temperature, a gas is compressed from 5.5 L to 1 L.

At 1 L, the pressure of the gas is 98.2 kPa

Generally the equation for Boyle's law   is mathematically given as

P1V1=P2V2

Therefore

P1=\frac{P2V2}{V1}\\\\P2=\frac{98.2*1}{5.5}

P2=17.854 kPa

For more information on Pressure visit

brainly.com/question/25688500

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