When Kb = 1.1 x 10^-6
∴ Ka = Kw / Kb
= 1.1 x 10^-14 / (1.1 x 10 ^-6)
= 1 x 10^-8
when the reaction equation when we assume the base is B
B + H2O ↔ BH+ + OH-
∴ Ka = [BH+][OH-]/[B]
1 x 10^-8 = X^2 / 0.49
X^2 = 4.9 x 10^-9
∴X = 7 x 10^-5
∴[OH-] = 7 x 10^-5
∴POH = -㏒[OH]
= -㏒7 x 10^-5
= 4.15
∴ PH = 14 - POH
14 - 4.15
= 9.85
As we know that there are avogadro no. of atoms in 9 g of beryllium.
1 mole of beryllium = 6.02 * 10^23 atoms
so 2.5 mole= 6.02*10^23*2.5 i.e = <span>15.055 × 10^23 atoms </span>
Answer:
54 grams of H₂O
Explanation:
4NH₃ + 3O₂ → 2N₂ + 6H₂O
Ratio is 4:6.
Let's convert the mass of ammonia in moles
Mass / Molar mass = Mol
34 g / 17 g/m = 2 moles
If 4 moles of ammonia are needed to produce 6 mol of water
2 mol of NH₃ will produce ( 2 .6 )/4 = 3 moles
Molar mass water = 18 g/m
Mass = mol . molar mass → 3 m . 18 g/m = 54 grams
An example is just when they have a a group o numbers, for any reason, and they want to find the average of then all
an example being um idk...numbers resulting from an experiment trying to find different densitys or something and they wanted to find the average density
Answer:
P₂ = 2.88 atm
Explanation:
Given data:
Initial volume of gas = 1.8 L
Final volume = 750 mL
Initial pressure = 17.5 Psi
Final pressure = ?
Solution:
We will convert the units first:
Initial pressure = 17.5 /14.696 = 1.2 atm
Final volume = 750 mL ×1L/1000L = 0.75 L
The given problem will be solved through the Boly's law,
"The volume of given amount of gas is inversely proportional to its pressure by keeping the temperature and number of moles constant"
Mathematical expression:
P₁V₁ = P₂V₂
P₁ = Initial pressure
V₁ = initial volume
P₂ = final pressure
V₂ = final volume
Now we will put the values in formula,
P₁V₁ = P₂V₂
1.2 atm × 1.8 L = P₂ ×0.75 L
P₂ = 2.16 atm. L/ 0.75 L
P₂ = 2.88 atm
