Answer:
Step-by-step explanation:
Divide by 23
Extract the square root.
(image) The figure below is an isosceles triangle surmounted by a semi-circle. Find the area of the entire region.
1 answer:
Answer:
12.53
Step-by-step explanation:
∠BCA = (180°-40°)/2 = 70°
Laws of Sines: CA/sin 40° = AB/sin 70° = 5/sin 70°
CA = 5/sin 70° * sin 40° = 3.40
area of semicircle CA = (3.1416 * 1.70²) / 2 = 4.54
By Heron's Formula, area of triangle ABC:
1/4 √(a+b+c) (a+b-c) (b+c-a) (c+a-b) = 1/4 * √13.4*3.4*3.4*6.6
= 7.99
Entire region area = 4.54 + 7.99 = 12.53
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Answer:
F. 2 1/9
Step-by-step explanation:
Step 1: Substitute q
When you plug in <em>n</em> = 1, 2, 3:
n(1) = 3
n(2) = 2.11111
n(3) = 2.3333
So our answer is F.