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anzhelika [568]
2 years ago
9

(image) The figure below is an isosceles triangle surmounted by a semi-circle. Find the area of the entire region.

Mathematics
1 answer:
S_A_V [24]2 years ago
5 0

Answer:

12.53

Step-by-step explanation:

∠BCA = (180°-40°)/2 = 70°

Laws of Sines: CA/sin 40° = AB/sin 70° = 5/sin 70°

CA = 5/sin 70° * sin 40° = 3.40

area of semicircle CA = (3.1416 * 1.70²) / 2 = 4.54

By Heron's Formula, area of triangle ABC:

1/4 √(a+b+c) (a+b-c) (b+c-a) (c+a-b) = 1/4 * √13.4*3.4*3.4*6.6

                                                          = 7.99

Entire region area = 4.54 + 7.99 = 12.53

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Answer:

48

Step-by-step explanation:

let s be the snowman, g be the girl, and t be the christmas tree

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2t+2ts=132

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subtract 2 times the first equation from the third one to get

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from the second equation we can deduce

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t=66/(1+s)

Substitute:

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3(66)/(1+s)=4s-22

3(66)=(4s-22)(1+s)

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using the quadratic formula, we get s = 10, s = -5.5.

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g=4

2t(1+10)=132

2t=12

t=6

So 2s+t*g= 20+6*4=48

you would get a different solution for the negative s, but since snowmen cannot be negative, 48 is the answe.r

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Step-by-step explanation:

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Step-by-step explanation:

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