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PIT_PIT [208]
2 years ago
14

List and define all of Newton’s laws of motion.

Physics
1 answer:
Luba_88 [7]2 years ago
6 0

Answer:

In the first law, an object will not change its motion unless a force acts on it. In the second law, the force on an object is equal to its mass times its acceleration. In the third law, when two objects interact, they apply forces to each other of equal magnitude and opposite direction.

Explanation:

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Heat from the surface is transferred underground by _______.
Ostrovityanka [42]
A, convection, is your answer
5 0
4 years ago
Read 2 more answers
A 120-V rms voltage at 1000 Hz is applied to an inductor, a 2.00-μF capacitor and a 100-Ω resistor, all in series. If the rms va
natima [27]

Answer:

The inductance of the inductor is 35.8 mH

Explanation:

Given that,

Voltage = 120-V

Frequency = 1000 Hz

Capacitor C= 2.00\mu F

Current = 0.680 A

We need to calculate the inductance of the inductor

Using formula of current

I = \dfrac{V}{Z}

Z=\sqrt{R^2+(L\omega-\dfrac{1}{C\omega})^2}

Put the value of Z into the formula

I=\dfrac{V}{\sqrt{R^2+(L\omega-\dfrac{1}{C\omega})^2}}

Put the value into the formula

0.680=\dfrac{120}{\sqrt{(100)^2+(L\times2\pi\times1000-\dfrac{1}{2\times10^{-6}\times2\pi\times1000})^2}}

L=35.8\ mH

Hence, The inductance of the inductor is 35.8 mH

4 0
3 years ago
Read 2 more answers
4. A motorist travels 406 km during a 9.0 hr period. What was the average speed in km/hr and m/s?
user100 [1]

Answer:

45.11 kmph and 12.530 m/s

Explanation:

Average speed = Total distance travelled / Total time taken

406/9 gives the answer in kilometers

And we convert it to m/s by multiplying it with 1000/3600

6 0
3 years ago
A T-bar tow is required to pull 85 skiers up a 600 m slope inclined at 15° above horizontal at a speed of 2.5 m/s. The coefficie
dalvyx [7]

Answer:

P = 1.45 hp or 1.94kW

Explanation:

Given:

v = 2.5m/s

uk = 0.06

m = 60kg

Fk = uk*m*g*fsin(15)

Fk = 0.06*85*9.81*60*sin(15)

Fk = 776.15 N

Power=force*speed

P = F*v

P = 776.15N*2.5m/s

P = 1940.36 W

1 Horsepower = 0.7457 Kilowatts

P = 1.45 hp

5 0
3 years ago
A cannon fires a cannonball of mass 16.0 kg by applying a force of 2750 N along the 1.25 m length of the barrel. (a) How much wo
Zarrin [17]

To develop this problem it is necessary to apply the concepts related to Work and energy conservation.

By definition we know that the work done by a particle is subject to the force and distance traveled. That is to say,

W = F*d

Where,

F= Force

d = Distance

On the other hand we know that the potential energy of a body is given based on height and weight, that is

PE = -mgh

The total work done would be given by the conservation and sum of these energies, that is to say

W_{net} = W+PE

PART A) Applying the work formula,

W = F*d\\W = 2750*1.25\\W = 3437.5J

PART B) Applying the height equation and considering that there is an angle in the distance of 25 degrees and the component we are interested in is the vertical, then

PE = -mgh*sin25

PE = -16*9.81*1.15sin25

PE = -82.9J

The net work would then be given by

W_{net} = W+PE

W_{net} = 3437.5J-82.9J

W_{net} = 3354.6J

Therefore the net work done by these 2 forces on the cannonball while it is in the cannon barrel is 3355J

3 0
3 years ago
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