Answer:
Explanation:
N₂ + 3 H₂ → 2 NH₃
1 mole 3 moles 2 moles
3.45 moles 10.35moles 6.90 moles
So 3.45 moles of nitrogen will require 10.35 moles of hydrogen
But hydrogen available is only 4.85 so this gas is the limiting reagent and product will be formed according to its mass .
a )
3 moles of hydrogen can form 2 moles of ammonia
4.85 moles of hydrogen will form 2 x 4.85 / 3 moles of ammonia
= 3.23 moles .
b ) hydrogen is the limiting reagent .
c ) Excess reactant is nitrogen
3 moles hydrogen need 1 mole of nitrogen
4.85 moles of hydrogen will need 4.85 / 3 moles of nitrogen
= 1.62 moles of nitrogen .
excess nitrogen = 3.45 - 1.62
= 1.83 moles.
Iron gains three electrons
Answer:
940 J
Explanation:
This is a calorimtetry excersie where you apply the formula
Q = C . m . ΔT
We only have 2 data from here, C and ΔT (from the solution)
C → 3.97 J/g°C
ΔT → 2.3°C
We determine the solution's mass by density:
1.03 g/mL = Solution mass / Solution volume
We assume the HCl as the solution volume → 100 mL
1.03 g/mL . 100 mL = 103 g → solution's mass
We replace data: Q = 103 g . 3.97 J/g°C . 2.3°C → 940.4 J
Answer:
1200 mL
Explanation:
Given data
- Initial pressure (P₁): 600.0 mmHg
- Initial volume (V₁): 400.0 mL
- Final pressure (P₂): 200.0 mmHg
For a gaseous sample, there is an inverse relationship between the pressure and the volume. If we consider the gas as an ideal gas, we can find the final volume using Boyle's law.
![P_1 \times V_1 = P_2 \times V_2\\V_2 = \frac{P_1 \times V_1}{P_2} = \frac{600.0mmHg \times 400.0mL}{200.0mmHg}=1200 mL](https://tex.z-dn.net/?f=P_1%20%5Ctimes%20V_1%20%3D%20P_2%20%5Ctimes%20V_2%5C%5CV_2%20%3D%20%5Cfrac%7BP_1%20%5Ctimes%20V_1%7D%7BP_2%7D%20%3D%20%5Cfrac%7B600.0mmHg%20%5Ctimes%20400.0mL%7D%7B200.0mmHg%7D%3D1200%20mL)