Using the conservation of momentumwhere momentum = mass x velocity
so the let x be the initial velocity of the ball B
(30 kg) (-10 m/s) + (10 kg) (x) = (30 kg) (30 m/s) + ( 10 kg) (-10 m/s)
-300 + 10 x = 900 - 10010x = 900 - 100 + 30010x = 1100x = 1100 / 10x = 110 m/s
Answer:
Speed of the sound in air is 325 m/s
Explanation:
As we know that the frequency of the sound is given as
wavelength of the sound is given as
now we have
so we have