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2 years ago

How might nutrients make their way from downstream to the upstream headwaters of the river?

1 answer:

3 0

Answer: A stream carves its path through a watershed, eroding nutrients from the soil and rock, or taking them from plants.

Explanation: Because, those nutrients flow through different branches of the food web. They may stay in that watershed for a long time or they may leave.

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A compound distributes between benzene (solvent 1) and water (solvent 2) with a distribution coefficient, K = 2.7. If 1.0g of th

mote1985 [20]

Explanation:

The given data is as follows.

Solvent 1 = benzene, Solvent 2 = water

$K_{p}$ = 2.7, $V_{S_{2}}$ = 100 mL

$V_{S_{1}}$ = 10 mL, weight of compound = 1 g

Extract = 3

Therefore, calculate the fraction remaining as follows.

$f_{n} = [1 + K_{p}(\frac{V_{S_{2}}}{V_{S_{1}}})]^{-n}$

= $[1 + 2.7(\frac{100}{10})]^{-3}$

= $(28)^{-3}$

= $4.55 \times 10^{-5}$

Hence, weight of compound to be extracted = weight of compound - fraction remaining

= 1 - $4.55 \times 10^{-5}$

= 0.00001

or, = $1 \times 10^{-5}$

Thus, we can conclude that weight of compound that could be extracted is $1 \times 10^{-5}$ .

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3 years ago

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Nuclear energy is released during:

kondaur [170]

B, C and E. In radioactive decay unstable atoms stabilize by releasing energy.

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3 years ago

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Rpd pls ii test :)<br><br> tot ce se afla in poza

mamaluj [8]

Answer:

Sorry mate! I can't understand this language...

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3 years ago

What is the difference between a conductor and an insulator?

USPshnik [31]

Answer:materials that impede the free flow of electrons from atom to atom and molecule to molecule.

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2 years ago

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How much heat is required to vaporize 25g of water at 100*c

ElenaW [278]

Answer:

Heat required = 13,325 calories or 55.75 KJ.

Explanation:

To convert a water to steam at 100 degree celsius to vapor, we have to give latent heat of vaporization to water

Which equals ,

Q = mL,

Where, m is the mass of water present

L = specific latent heat of vaporization

Here , m= 25 gram

L equals to 533 calories (or 2230 Joules)

So, Q = 25×533 = 13,325 Calories

Or , Q = 55,750 Joules = 55.75 KJ

so, Heat required = 13,325 calories or 55.75 KJ.

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3 years ago