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lianna [129]
3 years ago
15

Which set of work should be used to solve the following problem?

Chemistry
1 answer:
VladimirAG [237]3 years ago
7 0

Answer:

C. 65.5 g PF3 x (1 mole / 87.97 g PF3)

Explanation:

Dimensional analysis can be used to find the amount of moles in 65.5 grams of PF3 gas.

First we would need to determine relevant conversions.

We would need to find the molar mass of PF3 which is already given ( 87.97 g / mol )

So 1 mole of PF3 = 87.97g

From there we can create the dimensional analysis table which will look something like the attached image.

This table correspond with answer choice C.

<u>Reasons </u><u>it's </u><u>not </u><u>the </u><u>other </u><u>answer </u><u>choices</u><u>.</u>

It wouldn't be A because the units must cancel out and they don't as grams is being multiplied by grams

It would be B because it doesn't use correct units.

There are not 87.97 moles in 1 gram of PF3. There are 87.97 grams in 1 mole of PF3

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Using bond lengths in Table 9.2 (p. 371) and assuming ideal geometry, calculate each of the following distances:
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Using complete sentences, explain how to predict the products and balance the reaction between sulfuric acid and potassium hydro
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3 years ago
The ksp of cadmium hydroxide, cd(oh)2, is 7.20 × 10-15. calculate the solubility of this compound in g/l.
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When the solubility is the amount of solute that dissolved in a unit volume of the solvent.

and when the balanced reaction equation is:

so, by using the ICE table:

            Cd(OH)2(s) ↔  Cd2+  +  2OH- 

initial                               0             0

change                          +X           +2X

Equ                                  X             2X

so the Ksp expression = [Cd2+] [OH-]^2 

and we have Ksp = 7.2 x 10^-15

and when we assume the solubility = X
  
by substitution:

7.2 x 10^-15 = (X) (2X)^2

7.2 x 10^-15 = X*4X^2

7.2 x 10^-15 = 4X^3

∴X = ∛(7.2x10^-15)/4

      = 1.22 x 10^-5 M

∴ the solubility = X = 1.22 x 10^-5 M
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