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mixer [17]
3 years ago
7

Calculate the force experienced by a positive test charge of 8.1 × 10-9 coulombs if the electric field strength is 9.4 × 107 new

tons/coulomb.
Physics
2 answers:
Arte-miy333 [17]3 years ago
5 0
The electric force exerted by an electric field of intensity E on a charge q is equal to the product between E and q, so:
F=qE=(8.1 \cdot 10^{-9}C)(9.4 \cdot 10^7 N/C)=0.76 N
Dominik [7]3 years ago
3 0
C.) 7.6<span>×10^-1 :) your welcome

</span>
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