Calculate the force experienced by a positive test charge of 8.1 × 10-9 coulombs if the electric field strength is 9.4 × 107 new
2 answers:
You might be interested in
The alpha particle is emitted at 4235 m/s
Explanation:
We can use the law of conservation of momentum to solve the problem: the total momentum of the original nucleus must be equal to the total momentum after the alpha particle has been emitted. Therefore:
where:
is the mass of the original nucleus
is the initial velocity of the nucleus
is the mass of the alpha particle
is the final velocity of the alpha particle
is the mass of the daughter nucleus
is the final velocity of the nucleus
Solving for , we find the final velocity of the alpha particle:
Learn more about momentum:
#LearnwithBrainly
Answer:
(a)11.24 m/s
(b)7.44 m/s
(c)409 N
(d)
(e) 0
Explanation:
The period for 1 circle of the merry go around is 9.5s. It means the angular speed is:
(a)The speed is
(b) Centripetal acceleration:
(c) Magnitude of the force that keeps you go around at this acceleration
(d) let the coefficient of friction by . The frictional force shall be this coefficient multiplied by normal force reverting gravity of the man