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kodGreya [7K]
3 years ago
6

Segmented mirrors sag under their own weight. their optical shape must be controlled by computer-driven thrusters under the mirr

ors in what is called an achromatic lens. active optics. a schmidt-cassegrain design. a newtonian design. interferometry.
Physics
1 answer:
madam [21]3 years ago
6 0
Active Optics.


Hope that helps, Good luck! (:
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The total capacitance of two 15uF capacitors<br> connected in parallel is
Yuri [45]

The total capacitance of two 15uF capacitors  connected in parallel is <em>30 μF</em> .

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3 years ago
State Pascal's principle of transmission of pressure​
bulgar [2K]

Answer:

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4 years ago
What do you need to make 100 minutes charges neutral
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Neutrons are neutral<span> and </span>do<span> not </span>have<span> any </span>charge<span> at all. Protons carry a positive </span>charge<span>, and electrons carry the negative </span><span>charge.</span>
4 0
3 years ago
| A 1.0 kg stone is dropped from a bridge 100 m above a canyon. What will be the kinetic energy of the stone after it
Mnenie [13.5K]

Answer:

Option D

490 J

Explanation:

When at a height of 100 am above and released, the ball initially posses only potential energy. When it falls, some potential energy is converted to kinetic energy.

Initial potential energy= mgh where m is the mass, g is the acceleration due to gravity and h is height. Substituting 1 Kg for m, 9.81 for g and 100 m for h then

PE initial = 1*9.81*100= 981 J

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Subtracting PE at 50 m from initial PE we get the energy that has been converted to kinetic energy hence

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Approximately, 490 J

8 0
3 years ago
The mass of jupiter is 300 times the mass of the earth. Jupiter orbits the sun with Tjupiter = 11.9 yr in an orbit with Rjupiter
mihalych1998 [28]

Answer:

c) 11.9 yr

Explanation:

The orbital period is proportional to r^(3/2) and does not depend on the satellite's mass. Any object at Jupiter position will have the same orbital period regardless of mass.

By keppler's law  we know that

T^2= r^3

T= orbital time period

r= mean distance of the planet from the Sun.

clearly, The orbital period does not depend on the satellite's mass

there, the correct answer will be c= 11.9 yr.

5 0
3 years ago
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