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2 years ago

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What can be said in general about warm colours

1 answer:

AleksAgata [21]2 years ago

3 0

Answer:

Warm colours are those with a yellow-ish or black undertone. Imagine how everything looks through your tinted sunglasses or on a beautiful day in autumn when the leaves are falling. The hints of yellow give these colours a sunny warmth, while those with more black mixed in appear darker and can seem more muted.

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A(n) 60.3 g ball is dropped from a height of 53.7 cm above a spring of negligible mass. The ball compresses the spring to a maxi

Feliz [49]

Answer:

271.862 N/m

Explanation:

From Hook's Law,

mgh = 1/2ke²............... Equation 1

Where

m = mass of the ball, g = acceleration due to gravity, k = spring constant, e = extension, h = height fro which the ball was dropped.

Making k the subject of the equation,

k =2mgh/k²....................... Equation 2

Note: The potential energy of the ball is equal to the elastic potential energy of the spring.

Given: m = 60.3 g = 0.0603 kg, g = 9.8 m/s², e = 4.68317 cm = 0.0468317 m, h = 53.7 cm = 0.537 m

Substitute into equation 2

k = 2(0.0603)(9.8)(0.537)/0.048317²

k = 0.6346696/0.0023345

k = 271.862 N/m

7 0

3 years ago

Which one of the following temperatures is equal to 5°C?

natali 33 [55]

Answer : The correct option is, (D) 278 K

Explanation :

We are given temperature $5^oC$ .

Now the conversion factor used for the temperature is,

$K=^oC+273$

where, K is kelvin and $^oC$ is Celsius.

Now put the value of temperature, we get

$K=5^oC+273=278K$

Therefore, the temperature 278 K is equal to the $5^oC$

7 0

3 years ago

The force required to stretch a Hooke’s-law spring varies from 0 N to 63.5 N as we stretch the spring by moving one end 5.31 cm

Alika [10]

Answer:

Force constant will be 1195.85 N/m

Work done will be 1.6859 J

Explanation:

We have given the force, F = 63.5 N

Spring is stretched by 5.31 cm

So x = 0.0531 m

Force is given , F = 63.5 N

We know that force is given by $F=kx$

So $63.5=k\times 0.0531$

k = 1195.85 N/m

Now we have to find the work done

We know that work done is given by

$W=\frac{1}{2}kx^2=\frac{1}{2}\times 1195.85\times 0.0531^2=1.6859J$

8 0

2 years ago

A single frictionless roller-coaster car of mass m = 750. kg tops the first hill with speed v = 15.0 m/s at height h = 20.0 m as

Law Incorporation [45]

i will give you 25 points sorry becuase i can't help with that

3 0

2 years ago

Tina drove 3 miles north and 4 miles west to get to her grandmother’s house. Find the distance and displacement.

TEA [102]

Answer:

distance = 3 + 4 = 7 mi

displacement is √(3² + 4²) = 5 mi

Explanation:

6 0

2 years ago