The answer is D my brother
N-Octanol and water are chosen because the connection between a substance's hydrophilicity and lipophilicity is measured by
(n-Octanol/Water partition coefficient). When a chemical is more dissolves in fat-like solvents like n-octanol, the value is more significant than one, when it's more dissolved in water, the value is lower.
What is the partition coefficient?
- The partition coefficient for the two-phase network comprising n-octanol and water is known as the
value. N-Octanol-Water Partition Ratio is another name for it.
- The connection between a substance's hydrophilicity (its ability to dissolve in water) and lipophilicity (its ability to dissolve in fat) is measured by
. The value is bigger if a drug is more accessible in fat-like liquids like n-octanol and less if a compound seems more water-soluble.
- Owing to linkage or fragmentation, substances that are involved in the octanol-water combination as multiple synthetic entities are each given a unique
ratio.
So, N-Octanol is chosen because it has a carbon/oxygen ratio that is comparable to that of lipids and because it shows both hydrophobic and hydrophilic properties. N-octanol, therefore, resembles the makeup and characteristics of cells and other living things.
Learn more about octanol here:
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First, we write the half equations for the reduction of the chemical species present:
Cu⁺² + 2e → Cu; E° = 0.34 V
Ni⁺² + 2e → Ni; E° = - 0.23 V
In order to determine the potential of the cell, we find the difference between the two values. For this:
E(cell) = 0.34 - (-0.23)
E(cell) = 0.57 V
The second option is correct. (The difference in values is due to different values in literature, and it is negligible)
Answer:B
Explanation:Coefficient represents the number of units of each substance.
<h2>Hello!</h2>
The answer is:
The new volume is equal to 206.5 L.
<h2>Why?</h2>
To solve this problem, we need to assume that the pressure is constant, and use the Charle's Law equation, so, solving we have:

We are given:

Then, using the Charle's Law equation, we have:


Hence, we have that the new volume is equal to 206.5 L.
Have a nice day!