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Advocard [28]
2 years ago
5

The radius of a circle is 11 cm. Find the circumference to the nearest tenth

Mathematics
1 answer:
Rainbow [258]2 years ago
7 0

Answer:

69.1 cm (nearest tenth)

Step-by-step explanation:

Circumference of circle= 2πr, where r is the radius.

Given that r= 11 cm,

circumference of the circle

= 2(π)(11)

= 22π

= 69.1 cm (nearest tenth)

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Pls help and show workings <br> (If you don’t know the answer please don’t respond)
raketka [301]

Answer:

the required postulate which should be used here to make the triangles congruent is

C. ASA , okay

Step-by-step explanation:

because, one side and one angle of both triangles are equal and one of angles of the both triangles are vertically opposite angles , hence they are also equal , so we get an angle, a side and one another angle equal to corresponding side and angles of other triangles , so required postulate is C. ASA

I hope it helped

8 0
3 years ago
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Parallel lines <br><br> What is the segment
Helga [31]

Answer:

Step-by-step explanation:

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2 years ago
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What is the common ratio of 17, 51, 153, 459,.....
adelina 88 [10]

Answer:

3

Step-by-step explanation:

17 * 3 = 51

51 * 3 = 153

153 * 3 = 459

etc.

8 0
2 years ago
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Scott is four more than double the age of Todd. Scott is 56. What is Todd's age?
SSSSS [86.1K]

Answer: 26 years old

Step-by-step explanation:

Since Scott is four more than double the age of Todd, start by taking away four from Scott's age.

56-4=52

Then take half of that because that would be double of Todd's age

52/2=26

Todd is 26 years old.

5 0
2 years ago
What is the measure of arc EF in circle H?<br> O 41°<br> O 50°<br> O 114<br> O 1730
timurjin [86]

Answer:

The measure of arc EF = 41°

Step-by-step explanation:

Given:

Arc DE = 73°

\angle FED=123\°

Now, we know from central angle theorem that the measure of central angle by an arc is twice that of the angle made by the same arc at the circumference. Therefore,

\textrm{Major Arc DGF}=2\times \angle FED\\\textrm{Major Arc DGF}=2\times 123\\\textrm{Major Arc DGF}=246\°

Now, we know that sum of all arcs on a circle is equal to 360°.

Therefore, arc DGF + arc DE + arc EF = 360°

246+73+arc\ EF=360\\319+arc\ EF=360\\arc\ EF=360-319=41\°

Therefore, the measure of the arc EF is 41°.

7 0
3 years ago
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