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natka813 [3]
3 years ago
11

If at a particular instant and at a certain point in space the electric field is in the x-direction and has a magnitude of 3.10

V/mV/m , what is the magnitude of the magnetic field of the wave at this same point in space and instant in time
Physics
1 answer:
Setler79 [48]3 years ago
8 0

Answer:

B = 1.03 10⁻⁸ T

Explanation:

For an electromagnetic wave, the electric and magnetic fields must oscillate in phase so that they remain between them at all times, otherwise the wave will extinguish

       

This relational is expressed by the relation

           E /B = c

           B = E / c

let's calculate

            B = 3.10 / 3 10⁸

            B = 1.03 10⁻⁸ T

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What is one way the biosphere can affect the geosphere
erica [24]

Answer: B

Explanation:

Biosphere breaks down rock of the geosphere (plant roots), but when it comes to soil, minerals of the geosphere feed the plants. Biosphere and atmosphere interact through animal and plant respiration of oxygen and carbon dioxide. Geosphere creates, destroys and keeps various biosphere places safe.

3 0
3 years ago
Read 2 more answers
Atmospheric conditions near a mountain range are such that a cloud at an altitude of 2.00 km contains 3.20 ✕ 10^7 kg of water va
kykrilka [37]

Answer:

time required is 6.72 years

Explanation:

Given data

mass m = 3.20 ✕ 10^7 kg

height h = 2.00 km = 2 × 10^3 m

power p = 2.96 kW  =2.96 × 10^3 J/s

to find out

time period

solution

we know work is mass × gravity force × height

and power is work / time

so we say that power =  mass  gravity force × height / time

now put all value and find time period

power =  mass × gravity force × height / time

2.96 × 10^3 =  3.20 ✕ 10^7  × 9.81× 2 × 10^3  / time

time =  62.784 × 10^10 / 2.96 × 10^3

time = 21.21081081 × 10^7 sec

time = 58.91891892 × 10^3 hours

time = 6.72 years

so time required is 6.72 years

3 0
3 years ago
A car on a roller coaster loaded with passengers has a mass of 2.0 x 10^3 kg. At the lowest point of the the track, the radius o
mart [117]

Answer:

here is my work

Explanation:

6 0
3 years ago
A photographer in a helicopter ascending vertically at a constant rate of accidentally drops a camera out the window when the he
maksim [4K]

Answer:

The time it takes for the camera to reach the ground is 5 s.

Explanation:

To solve this problem, we will use the free fall cinematic equation.

Since the helicopter ascends with constant speed, the camera falls to the ground only by the effect of gravity on it.

The speed at which the helicopter ascends is not specified in the statement, but according to a similar problem, we will use 12.5 \frac{m}{s}.

First, we must calculate the time and the maximum height at which the camera arrives after leaving the helicopter.

To calculate the maximum height to which it arrives, we will use the formula of vertical shot (since the camera leaves the helicopter with a speed upwards of 12,5 \frac{m}{s}).

V_{f} ^{2}=V_{0} ^{2} - 2 * g * h

Where:

V_{f}: final speed at maximum height.

V_{0}: initial speed when it falls from the helicopter.

g: gravity taken at 9.8 \frac{m}{s^{2} }

h: height reached from 60 m when leaving the helicopter

as V_{f}=0

0=(12,5\frac{m}{s}) ^{2} - 2 * 9,8\frac{m}{s^{2} } * h

clear h:

h=(12,5 \frac{m}{s^{2} } )^{2} / (2 * 9,8 \frac{m}{s^{2} })

h=7,97 m

Then we must calculate the time it takes to reach its maximum height:

V_{f}=V_{0} - g * t

t: time it takes to arrive from the moment it leaves the helicopter at its maximum height.

as V_{f}=0

0=12.5 \frac{m}{s} - 9.8 \frac{m}{s^{2} } * t

clearing t

t=12.5 \frac{m}{s} / 9.8 \frac{m}{s^{2} }

t=1.27 s.

Now we can calculate the time it takes to fall from the maximum height of 67.97 m.

The equation we will use is Y=v_{0}*t+(\frac{g*t^{2} }{2} )

where:

t: time it takes for the camera to fall.

Y: height from where the camera falls concerning the ground.

v_{0}: initial speed of the camera at the time of starting the fall.

g: acceleration of gravity, estimated at 9.8 \frac{m}{s^{2} }

Step 1: As the helicopter ascends with constant speed, the initial speed of the camera at the moment of falling is 0.

v_{0}=0

So the first term of our equation is nullified.

Step 2: To calculate the time it takes to fall, we clear "t" of the equation:

Y=\frac{(g*t^{2})}{2}

Y*2=(g*t^{2})

\frac{Y*2}{g}=t^{2}

\sqrt{\frac{Y*2}{g} }=t

Step 3: I replace the values with the incognites and get "t".

t=\sqrt{\frac{67,97m*2}{9,8\frac{m}{s^{2} } } }

t=3,73 s

The total time it takes for the camera to fall from the moment it leaves the helicopter is the sum of the time it takes to reach the maximum point of height and the time it takes to fall to the ground from that height.

t= 1,27 s + 3,73 s = 5 s

Have a nice day!

3 0
4 years ago
PLEASE HELP!! explain the advantages of operating a motor vehicle that is 20% efficient instead of one that is 10 % efficient
sladkih [1.3K]
Well, one is more effeciant than the other. I think it would run on less gass.
7 0
3 years ago
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