A 25.0 kg object moving at +15.0 m/s strikes a 15.0 kg
1 answer:
The final velocity of the 15 kg mass is 18.33 m/s.
<h3>Conservation of linear momentum</h3>The final velocity of the 15 kg mass can be determined by applying the principles of conservation of linear momentum as follows;
Where;
- m₁ is the mass of the first object = 25 kg
- u₁ is the initial velocity of the first object = 15 m/s
- m₂ is the mass of the second object = 15 kg
- u₂ is the initial velocity of the second object = -10 m/s
- v₁ is the final velocity of the first object = -2 m/s
- v₂ is the final velocity of the second object
Thus, the final velocity of the 15 kg mass after the collision is 18.33 m/s.
Learn more about conservation of linear momentum here: brainly.com/question/7538238
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Answer:
s = 1.7 m
Explanation:
from the question we are given the following:
Mass of package (m) = 5 kg
mass of the asteriod (M) = 7.6 x 10^{20} kg
radius = 8 x 10^5 m
velocity of package (v) = 170 m/s
spring constant (k) = 2.8 N/m
compression (s) = ?
Assuming that no non conservative force is acting on the system here, the initial and final energies of the system will be the same. Therefore
• Ei = Ef
• Ei = energy in the spring + gravitational potential energy of the system
• Ei = \frac{1}{2}ks^{2} + \frac{GMm}{r}
• Ef = kinetic energy of the object
• Ef = \frac{1}{2}mv^{2}
• \frac{1}{2}ks^{2} + (-\frac{GMm}{r}) = \frac{1}{2}mv^{2}
• s =
s =
s = 1.7 m