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2 years ago

A 25.0 kg object moving at +15.0 m/s strikes a 15.0 kg

Physics

1 answer:

lesya692 [45]2 years ago

8 0

The final velocity of the 15 kg mass is 18.33 m/s.

<h3>Conservation of linear momentum</h3>

The final velocity of the 15 kg mass can be determined by applying the principles of conservation of linear momentum as follows;

$m_1 u_1 + m_2 u_2 = m_1 v_1 + m_2 v_2\\\\$

Where;

m₁ is the mass of the first object = 25 kg
u₁ is the initial velocity of the first object = 15 m/s
m₂ is the mass of the second object = 15 kg
u₂ is the initial velocity of the second object = -10 m/s
v₁ is the final velocity of the first object = -2 m/s
v₂ is the final velocity of the second object

Thus, the final velocity of the 15 kg mass after the collision is 18.33 m/s.

Learn more about conservation of linear momentum here: brainly.com/question/7538238

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Answer:

Explanation:

mass of 1 L water = 1 kg .

200⁰F = (200 - 32) x 5 / 9 = 93.33⁰C .

260.928 K = 260.928 - 273 = - 12.072⁰C .

water is at higher temperature .

Let the equilibrium temperature be t .

Heat lost by water = mass x specific heat x fall of temperature

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Heat gained by copper

= .25 x .385 x 10³ x ( t + 12.072 )

Heat lost = heat gained

1 x 4.2 x 10³ x ( 93.33 - t ) = .25 x .385 x 10³ x ( t + 12.072 )

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2 years ago

A skier is pulled by a towrope up a frictionless ski slope that makes an angle of 12 degrees with the horizontal. The rope moves

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Answer:

Explanation:

Given,

Work done by the rope 900 m/s.
Angle of inclination of the slope = $\theta\ =\ 12^o$
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part (a)

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part (b)

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3 years ago

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Answer:

$T_f=24.71$

Explanation:

From the question we are told that:

Mass of block $m=50$

Temperature of block $T_b =140 \textdegree C$

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Temperature of water $T_w=10 \textdegree C$

Density of water $\rho=1000kg/m^3$

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Answer:

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