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2 years ago

What is the peak power consumption of a 120-v ac microwave oven that draws 10. 0 a.

Physics

1 answer:

Lina20 [59]2 years ago

7 0

The peak power consumption of a 120-V AC microwave oven that draws 10.0 A? is 2400 W.

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If the angle of incidence of a light source to a shiny surface is 30 degrees, what will the angle

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<h3>Answer: D) 30</h3>

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How do volcanoes above hot spots differ from volcanoes above subduction zones?

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What is climate change? How is it caused

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climate change is a change in climate in the Earth 's normal weather patterns for different climates. it normally changes little by little over the years.the earth is cooler and warming .now it's getting warmer. this phenomenon is also known by as globall warming.it's causes are:

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A greenhouses is made from glass or clear plastic. It is useful for growing plants in winter in cooler climates.

sorry i don't know last one .

The 2015 United Nations Climate Change Conference, COP 21 or CMP 11 was held in Paris, France, from 30 November to 12 December 2015.

End date: 12 December 2015

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Explanation:

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3 years ago

An egg suspended above the ground has 93.1 J of gravitational potential energy. The egg is then dropped and falls to the ground.

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3 years ago

A uniform cylinder of radius 10 cm and mass 20 kg is mounted so as to rotate freely about a horizontal axis that is parallel to

fomenos

Answer:

a. 0.15 kg m2

b. 19.8 rad/s

Explanation:

Metric unit conversion:

10 cm = 0.1 m

5 cm = 0.05 m

a. Using parallel axis theorem, the rotational inertia of the cylinder about the axis of rotation is the inertia about the longitudinal axis plus the product of mass and distance from the longitudinal axis to the rotational axis squared

$I = I_L + md^2$

whereas the inertia about the longitudinal axis of the solid cylinder is

$I_L = mr^2/2 = 20*0.1^2/2 = 0.1 kgm^2$

$md^2 = 20*0.05^2 = 0.05 kgm^2$

$I = I_L + md^2 = 0.1 + 0.05 = 0.15 kg m^2$

b. Assume the cylinder does not rotate about its own longitudinal axis, we can treat this as a point mass pendulum. So when it's being released from 0.05m high (release point) to 0m (lowest position), its potential energy is converted to kinetic energy:

$E_p = E_k$

$mgh = mv^2/2$

where h = 0.05 is the vertical distance traveled, v is the cylinder linear velocity at the lowest position.g = 9.81m/s2 is the gravitational acceleration.

We can divide both sides by m

$gh = v^2/2$

$v^2 = 2gh = 2*9.81*0.05 = 0.981$

$v = \sqrt{0.981} = 0.99 m/s$

The angular speed is linear speed divided by the radius of rotation, which is distance from the cylinder center to the center of rotation d = 0.05 m

$\omega = \frac{v}{d} = \frac{0.99}{0.05} = 19.8 rad/s$

5 0

3 years ago