Question

A simple pendulum is 1.15 meters long and has a period of 6.29 seconds. The pendulum is on an unknown planet. What is the acceleration of gravity of the Unknown Planet

Answer 1

Answer:

The value of the acceleration of gravity of the Unknown Planet = 1.14 $\frac{m}{s^{2} }$

Explanation:

length of the pendulum (L)= 1.15 m

Time period (T)= 6.29 seconds

We know that time period  of a simple pendulum is given by

⇒ T = 2$\pi$ × $\sqrt\frac{L}{g}$

put the values in the above formula we get

⇒ T = 2$\pi$ × $\sqrt \frac{1.15}{g}$

⇒ 6.29 = 2$\pi$ × $\sqrt \frac{1.15}{g}$

By solving the above equation we get

⇒ g = 1.14 $\frac{m}{s^{2} }$

This is the value of the acceleration of gravity of the Unknown Planet.