Answer:
![c=71.4m/s](https://tex.z-dn.net/?f=c%3D71.4m%2Fs)
![\theta=8.54\textdegree](https://tex.z-dn.net/?f=%5Ctheta%3D8.54%5Ctextdegree)
Explanation:
From the question we are told that
Initial velocity of 60 m/s
Wind speed ![V_w= 15 m/s \angle 45 \textdegree](https://tex.z-dn.net/?f=V_w%3D%2015%20m%2Fs%20%5Cangle%20%2045%20%5Ctextdegree)
Generally Resolving vector mathematically
![sin(45\textdegree)15=10.6\\cos(45\textdegree)15=10.6](https://tex.z-dn.net/?f=sin%2845%5Ctextdegree%2915%3D10.6%5C%5Ccos%2845%5Ctextdegree%2915%3D10.6)
Generally the equation Pythagoras theorem is given mathematically by
![c^2=a^2+b^2](https://tex.z-dn.net/?f=c%5E2%3Da%5E2%2Bb%5E2)
![c^2=10.6^2 +(10.6+60)^2](https://tex.z-dn.net/?f=c%5E2%3D10.6%5E2%20%2B%2810.6%2B60%29%5E2)
![c=\sqrt{10.6^2 +(10.6+60)^2}](https://tex.z-dn.net/?f=c%3D%5Csqrt%7B10.6%5E2%20%2B%2810.6%2B60%29%5E2%7D)
Therefore Resultant velocity (m/s)
![c=71.4m/s](https://tex.z-dn.net/?f=c%3D71.4m%2Fs)
b)Resultant direction
Generally the equation for solving Resultant direction
![\theta=tan^-1(\frac{y}{x})](https://tex.z-dn.net/?f=%5Ctheta%3Dtan%5E-1%28%5Cfrac%7By%7D%7Bx%7D%29)
Therefore
![\theta=tan^-1(\frac{10.6}{70.6})](https://tex.z-dn.net/?f=%5Ctheta%3Dtan%5E-1%28%5Cfrac%7B10.6%7D%7B70.6%7D%29)
![\theta=8.54\textdegree](https://tex.z-dn.net/?f=%5Ctheta%3D8.54%5Ctextdegree)
The work done by the force is 47.1 J
Explanation:
The work done by a force in moving an object is given by
(1)
where
F is the magnitude of the force
d is the distance covered by the object
is the angle between the direction of the force and the motion of the object
In this problem, the force applied to the object is
F = 3.0 N
This force is always tangential to the track: this means that at every instant, the force is parallel to the motion of the object, so
![\theta=0](https://tex.z-dn.net/?f=%5Ctheta%3D0)
And the distance covered is equal to the circumference of the circle, which is:
![d=2\pi r=2\pi (2.5 m)=15.7 m](https://tex.z-dn.net/?f=d%3D2%5Cpi%20r%3D2%5Cpi%20%282.5%20m%29%3D15.7%20m)
where r = 2.5 m is the radius.
Now we can substitute into eq.(1) to find the work done:
![W=(3.0)(15.7)(cos 0)=47.1 J](https://tex.z-dn.net/?f=W%3D%283.0%29%2815.7%29%28cos%200%29%3D47.1%20J)
Learn more about work:
brainly.com/question/6763771
brainly.com/question/6443626
#LearnwithBrainly
<span>Weight of the skydiver m = 500 N
Terminal velocity V = 90 km/h
Here the weight of the person acts as the force, so based on the Newton's third law the applied is the force what we but in the opposite direction making the resistance. So the air resistance exerted on Suzie will be her weight that is 500N</span>
If an object that is 86kg on the moon then that is the answer, 86kg.
Answer:
Explanation:
Let the amplitude of individual wave be I and resultant amplitude be 1.703 I . Let the phase difference be Ф in terms of degree
From the formula of resultant vector
(1.703I)² = I² + I² + 2 I² cosФ
2.9 I² = 2I² + 2 I² cosФ
.9I² = 2 I² cosФ
cosФ = .9 / 2
= .45
Ф = 63.25 .