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scoray [572]
3 years ago
11

If the sum of all the forces acting on a car is zero, then the speed of the car?

Physics
1 answer:
Taya2010 [7]3 years ago
7 0

Answer: If all forces acting on a car are zero, than the cars speed is zero since there are no forces to push or pull the car :)

Explanation:

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A rock is dropped from the top of a tower. When it is 40 meters above the ground velocity of 17 m/s. When its velocity is 24 m/s
eimsori [14]

Answer:

Option B is the correct answer.

Explanation:

Let us consider 40 meter above ground as origin.

Initial velocity = 17 m/s

Final velocity = 24 m/s

Acceleration = 9.81 m/s

We have equation of motion v² = u² + 2as

Substituting

         24² = 17² + 2 x 9.81 x s

           s = 14.63 m

Distance traveled by rock = 14.63 m down.

Height of rock from ground = 40 - 14.63 = 25.37 m = 25.4 m

Option B is the correct answer.

4 0
4 years ago
Can someone help me please?
Drupady [299]
D is the right answer
5 0
3 years ago
imagine that you have a sample of an unknown element and that you know only the elements mass number without directly measuring
Ostrovityanka [42]
If the element's atomic mass is accurate enough you should be able to tell from that , however if it isn't you would most likely want the number of neutrons or electrons contained by the atom.
4 0
3 years ago
If the box moves at a constant velocity, what do you know about the forces acting on the object?
Anon25 [30]
The answer is A , the forces are balanced
6 0
3 years ago
Read 2 more answers
Transcranial magnetic stimulation (TMS) is a noninvasive technique used to stimulate regions of the human brain. A small coil is
Xelga [282]

Answer:

7.3114*10^{-5}V

Explanation:

To give a solution to the exercise, it is necessary to consider the concepts related to magnetic flux and Faraday's law of induction. Faraday's law states that the voltage induced in a closed circuit is directly proportional to the speed with which the magnetic flux that crosses any surface with the circuit as an edge changes over time.

It is represented under the equation,

\epsilon = N \frac{\Delta\Phi}{\Delta t}

Where,

\epsilonis the induced electromotive force

N = Number of loops

\Delta t= Time

\Delta\Phi= Magnetic Flux

For definition the change in magnetic flux is:

\Delta \Phi = \Delta B A cos\phi

Where,

B= Magnetic field

Substituting at the first equation we have

\epsilon = N \frac{\Delta B A Cos\phi}{\Delta t}

\epsilon = N \frac{(B_2-B_1) (\pi r^2) Cos\phi}{\Delta t}

Our values are given by,

N = 1 turn

B_2 = 1T

B_1 = 0T

r = 1.6mm

\phi = 0\°

\Delta t = 100ms

Replacing,

\epsilon = (1) \frac{(1-0) (\pi (1.6*10^{-3})^2) Cos(0)}{110*10^{-3}}

\epsilon = 7.311*10^{-5}V

<em>Therefore the magnitud of the induced emf around a horizontal circle of tissue is 7.3114*10^{-5}V</em>

8 0
4 years ago
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