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sergiy2304 [10]
2 years ago
5

5. Find the number of moles equal to 1.90 x 1025 molecules of Mg(OH)2

Chemistry
1 answer:
vodomira [7]2 years ago
5 0

Answer:1 grams Mg(OH)2 = 0.017146870490373 mole using the molecular weight calculator and the molar mass of Mg(OH)2.

Explanation:

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When filtered through a funnel into a flask, a mixture of substances X, Y and Z gets separated as below: - X stays in the funnel
alisha [4.7K]

Z is the solvent, Y is soluble in water while X is insoluble in water.

<h3>Filtration</h3>

Filtration is a method of separation of substances based on particle size. Only a particular particle size can pass through the filter. The substance that remains in the filter is the residue while the substances that passes through the filter is called the filtrate.

From the observation in the question Z is the solvent, Y is soluble in water while X is insoluble in water.

Learn more about separation of mixtures: brainly.com/question/863988

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3 years ago
What do a mole of magnesium (Mg) and a mole of iron (Fe) have in common?
azamat
What they have in common is that they both have the same number of atoms.
9 0
3 years ago
Three quantum numbers are derived from Schrodinger’s equation that describe the probability of finding an electron around a nucl
hodyreva [135]

Principle: Orbital size & main energy level

Angular: Orbital shape

Magnetic: Orbital orientation

Orbital size is Principle; main energy level is Principle; shape is Angular; orientation is Magnetic

Principle:

imagine a bullseye. each ring shows how far its from the nucleus

Angular:

0 looks like circle

1 looks like a bowtie

2 looks like a flower or 4 leaf clover

3 looks like multiple lobes

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brainly.com/question/16979660

3 0
2 years ago
How many protons, electrons, and neutrons does the following isotope contain? 79Br+
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6 0
3 years ago
Read 2 more answers
The ksp of copper(ii) carbonate, cuco3, is 1.4 × 10-10. calculate the molar solubility of this compound.
mafiozo [28]
As,
                              CuCO₃    ⇆  Cu²⁺  +  CO₃²⁻
So,
                             Kc  =  [Cu²⁺] [CO₃²⁻] / CuCO₃
Or,
                             Kc (CuCO₃)  =  [Cu²⁺] [CO₃²⁻]
Or,
                             Ksp  =  [Cu²⁺] [CO₃²⁻]
As,
Ksp  = 1.4 × 10⁻¹⁰
So,
                            1.4 × 10⁻¹⁰  =  [x] [x]
Or,
                             x²  =  1.4 × 10⁻¹⁰ 
Or,
                             x  =  1.18 × 10⁻⁵ mol/L
To cahnge ito g/L,
                             x  =  1.18 × 10⁻⁵ mol/L × 123.526 g/mol

                   
         x  =  1.45 × 10⁻³ g/L
3 0
3 years ago
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