Answer:
One way to find out is to change “passive mass” - the dirt and rocks of Earth - and convert it into “active mass” - add energy “E” to it. If we increase the energy “E” we will increase its mass. The key is, how do you turn “passive mass” into “active mass” by adding energy “E” to the “passive mass”? After all, isn’t “passive mass” of the Earth just the dirt and rocks that make up the planet?
Explanation:
Answer
% of C in C2H6= (2×12)/30×100=80%
% of H in C2H6= (3×2)/30×100=20%
Explanation:
2C+3H2-C2H6
nC=12, nH=1, nC2H6=30
2moles of C-1mole of C2H6
3moles of H-1 mole of C2H6
% of C in C2H6= (2×12)/30×100=80%
% of H in C2H6= (3×2)/30×100=20%
I think the correct answer from the choices listed above is option B. <span>24 mL of Mg burn in 32 mL O2 to produce 56 mL of MgO </span>does not show the law of conservation of mass. Volumes cannot be added because there are volume effects when you add different substances. So, the reactants is not equal to the product.
Answer:
2HCL
Explanation:
Both the elements have 2 so when placing the 2 infront ,it'll distribute/ apply to both
