Answer:
This is a coal combustion process and we will assume
Inlet coal amount = 100kg
It means that there are
15kg of H2O, 2kg of Sulphur and 83kg of Carbon
Now to find the mole fraction of SO2(g) in the exhaust?
Molar mass of S = 32kg/kmol
Initial moles n of S = 2/32 = 0.0625kmols
Reaction: S + O₂ = SO₂
That is 1 mole of S reacts with 1 mole of O₂ to give 1 mole of SO₂
Then, it means for 0.0625 kmoles of S, we will have 0.0625 kmole of SO2 coming out of the exhaust
The mole fraction of SO2(g) in the exhaust=0.0625kmols
Explanation:
Answer:
Where are the following?
Explanation:
The main properties of water are its polarity, cohesion, adhesion, surface tension, high specific heat, and evaporative cooling.
Answer:
5 Atoms
Explanation
We have one atom of Calcium, One Atom of Carbon and three of Oxygen
Ca(C2H302)2(aq) + Na2CO3(aq) —> CaCO3(s) + 2 NaC2H302(aq)
