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Degger [83]
2 years ago
5

Vector A points along the + y axis and a magnitude of 100.0 units. Vector B points at an angle of 60.0 degrees above the +x axis

and has a magnitude of 200.0 units. Vector C points along the +x axis and has a magnitude of 150.0 units. Which vector has (a ) the largest x component and (b) the largest y component ?
Physics
1 answer:
DedPeter [7]2 years ago
3 0

Answer:

vector quantities are resolved into their component form (along the x and y-axis) before adding them. Let us assume that two vectors are

→

a

=

x

1

^

i

+

y

1

^

j

and

→

b

=

x

2

^

i

+

y

2

^

j

, we can find the sum of two vectors as follows.

→

a

+

→

b

=

x

1

^

i

+

y

1

^

j

+

x

2

^

i

+

y

2

^

j

=

(

x

1

+

x

2

)

^

i

+

(

y

1

+

y

2

)

^

j

The direction of the sum of the vectors (with positive x-axis) is,

θ

=

tan

−

1

(

y

1

+

y

2

x

1

+

x

2

)

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monitta

Answer:

a) θ₁ = 23.14 ° , b) θ₂ = 51.81 °

Explanation:

An address network is described by the expression

     d sin θ = m λ

Where is the distance between lines, λ is the wavelength and m is the order of the spectrum

The distance between one lines, we can find used a rule of proportions

     d = 1/600

     d = 1.67 10⁻³ mm

    d = 1-67 10⁻³ m

Let's calculate the angle

    sin θ = m λ / d

    θ  = sin⁻¹ (m λ / d)

First order

    θ₁ = sin⁻¹ (1 6.5628 10⁻⁷ / 1.67 10⁻⁶)

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Second order

     θ₂ = sin⁻¹ (2 6.5628 10⁻⁷ / 1.67 10⁻⁶)

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3 0
3 years ago
A solid weighs 200N in air, 150N in water and 170N in a liquid. Find relative density of solid, relative density of liquid and d
fomenos

Answer:

\rho_{s} = 4

\rho_{l} = 0.6

\rho{liq} = 600 kg/m^{3}

Given:

Weight of solid in air, w_{sa} = 200 N

Weight of solid in water, w_{sw} = 150 N

Weight of solid in liquid, w_{sl} = 170 N

Solution:

Calculation of:

1. Relative density of solid, \rho_{s}

\rho_{s} = \frac{w_{sa}}{w_{sa} - w_{sw}}

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2. Relative density of liquid, \rho_{l}

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3. Density of liquid in S.I units:

Also, we know:

\rho{l} = \frac{\rho_{liq}}{\rho_{w}}

where

= {\rho_{liq}} = density of liquid

= {\rho_{w}} = 1000 kg/m^{3} = density of water

Now, from the above formula:

0.6 = \frac{\rho_{liq}}{1000}

\rho{liq} = 600 kg/m^{3}

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