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Degger [83]
2 years ago
5

Vector A points along the + y axis and a magnitude of 100.0 units. Vector B points at an angle of 60.0 degrees above the +x axis

and has a magnitude of 200.0 units. Vector C points along the +x axis and has a magnitude of 150.0 units. Which vector has (a ) the largest x component and (b) the largest y component ?
Physics
1 answer:
DedPeter [7]2 years ago
3 0

Answer:

vector quantities are resolved into their component form (along the x and y-axis) before adding them. Let us assume that two vectors are

→

a

=

x

1

^

i

+

y

1

^

j

and

→

b

=

x

2

^

i

+

y

2

^

j

, we can find the sum of two vectors as follows.

→

a

+

→

b

=

x

1

^

i

+

y

1

^

j

+

x

2

^

i

+

y

2

^

j

=

(

x

1

+

x

2

)

^

i

+

(

y

1

+

y

2

)

^

j

The direction of the sum of the vectors (with positive x-axis) is,

θ

=

tan

−

1

(

y

1

+

y

2

x

1

+

x

2

)

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Dafna1 [17]
Okay. If a car takes 2 hours to go 80 miles, the car is going 40 miles an hour. All you have to do is 80/2 in order to get your answer, because you do distance divided by time to find the speed.
8 0
3 years ago
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A sound wave traveling through a solid material has a frequency of 400 hertz. the wavelength of the sound wave is 2 meters. what
Pepsi [2]

Answer:

c. 800m/s

Explanation:

v = f × /\

v = 400 × 2

v = 800m/s

3 0
3 years ago
A car is moving with speed 60 m/s and acceleration 4 m/s2 at a given instant. (a) using a second-degree taylor polynomial, estim
pantera1 [17]

Answer:

Explanation:

Using second degree taylor polynomials

let S(t) be position function and set S(0)=0

where S(0) is the initial position

Then v(t) = S^i(t) and a(t)=S^{ii}(t)

we have v(0) = 60m/s, a(0) = 4m/s^2

so T_{2}(t) =S(0)+v(0)t+\frac{a(0)}{2} t^2\\\\\\=0+60t+\frac{4}{2} t^2\\\\T_{2}(t)=60t+2t^2\\\\S(1)=T_{2}(1)=60+2=62m

b.) yes

6 0
3 years ago
A 250 kg flatcar 25 m long is moving with a speed of 3.0 m/s along horizontal frictionless rails. A 61 kg worker starts walking
Anna11 [10]

Answer:

x=31.09m

Explanation:

p1=p2

The momentum of flatcar and the momentum of the worker so

The velocity of the worker is:

m_{f}*v_{f}=m_{w}*v_{w}\\\\v_{f}=\frac{m_{f}*v_{f}}{m_{w}}\\v_{f}=\frac{61kg*3.0\frac{m}{s}}{250kg}\\v_{f}=0.732\frac{m}{s}

The total motion has a total velocity and is

Vt=v_{w}+v_{f}\\Vt=0.732\frac{m}{s}+3.0\frac{m}{s}\\Vt=3.732\frac{m}{s}

The time the worker take walking is

t=\frac{x}{v_{w}}\\t=\frac{25m}{3\frac{m}{s}}=8.33s

Now the total time and the total velocity determinate the motion of tha flatcar how far has moved

x=t*Vt\\x=8.33s*3.732\frac{m}{s} \\x=31.09m

5 0
3 years ago
How do u do 5? Show me plz
nikitadnepr [17]
Solve the equation.it is hard to see
6 0
3 years ago
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