To
determine the empirical formula of the compound given, we need to determine the ratio of each element in the compound. To do that we assume to have 100 grams sample
of the compound with the given composition. Then, we calculate for the number
of moles of each element. We do as follows:<span>
mass moles
C 56.79 4.73
H 6.56 6.50
O 28.37 1.77
N 8.28 0.59
Dividing the number of moles of each element with
the smallest value, we will have the empirical formula:
</span> moles ratio
C 4.73 / 0.59 8
H 6.50 / 0.59 11
O 1.77 / 0.59 3
N 0.59 / 0.59 1<span>
</span><span>
The empirical formula would be C8H11O3N.</span>
Answer:
Option D
Explanation:
Molarity (M) of any solution is equal to the number of moles (n)of solute in it divided by total volume of solution (V)
Mathematically, it can be represented as

Substituting the given values, we get-

Hence, option D is correct
You have 1 mol of silicon atoms. Therefore you have its atomic mass in grams. The answer is 28.055 g of silicon.
H and O
CI and F
Mg and N
P and O
Cs and F
*should know them from the first letter very easy*
Answer:
The maximum number of moles of PH₃ that can be formed is 0.8 moles.
Explanation:
The balanced reaction is:
P₄ + 6 H₂ → 4 PH₃
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of each compound participate in the reaction:
- P₄: 1 mole
- H₂: 6 moles
- PH₃: 4 moles
The limiting reagent is one that is consumed first in its entirety, determining the amount of product in the reaction. When the limiting reagent is finished, the chemical reaction will stop.
To determine the limiting reagent, you can use a simple rule of three as follows: If by stoichiometry of the reaction 6 moles of hydrogen react with 1 mole of phosphorus, 4 moles of hydrogen will react with how many moles of phosphorus?

moles of phosphorus= 0.667
But 0.667 moles of phosphorus are not available, 0.2 moles are available. Since you have less moles than you need to react with 4 moles of hydrogen, phosphorus will be the limiting reagent.
Then you can apply the following rule of three: if by stoichiometry 1 mole of P₄ forms 4 moles of PH₃, 0.2 moles of P₄ will form how many moles of PH₃?

moles of PH₃= 0.8
<u><em>The maximum number of moles of PH₃ that can be formed is 0.8 moles.
</em></u>
<u><em></em></u>