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PtichkaEL [24]
2 years ago
8

What agricultural is practiced in or near San Diego? Choose a food that is grown or produced locally. Describe the food,Where an

d when is the food produced and how? What is a recipe that uses this food? What does this food make you wonder about the agriculture in or near San Diego?
please help!!
Chemistry
1 answer:
liraira [26]2 years ago
3 0

Answer:

San Diego boasts top crops in nursery, flowers, avocados, tomatoes, citrus, chickens & eggs, shrooms, succulents, strawberries, coffee & cannabis. Most of San Diego County farms are small 1-9 acre proprieties, and that awards San Diego County more certified organic growers than any other county in the nation.

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The compound adrenaline contains 56.79% c, 6.56% h, 28.37% o, and 8.28% n by mass. what is the empirical formula for adrenaline?
Phoenix [80]
To determine the empirical formula of the compound given, we need to determine the ratio of each element in the compound. To do that we assume to have 100 grams sample of the compound with the given composition. Then, we calculate for the number of moles of each element. We do as follows:<span>
         mass        moles
C       56.79        4.73
H       6.56          6.50
O       28.37        1.77
N      8.28           0.59

Dividing the number of moles of each element with the smallest value, we will have the empirical formula:

</span>         moles                 ratio
C       4.73     / 0.59       8
H       6.50     / 0.59      11
O       1.77     / 0.59       3
N        0.59    / 0.59       1<span>
</span><span>
The empirical formula would be C8H11O3N.</span>
8 0
3 years ago
What is the molarity of a solution made from dissolving 10.0 moles of NaOH into 5.0
Vladimir79 [104]

Answer:

Option D

Explanation:

Molarity (M) of any solution is equal to the number of moles (n)of solute in it divided by total volume of solution (V)

Mathematically, it can be represented as

M = \frac{n}{V}

Substituting the given values, we get-

M = \frac{10}{5} = 2

Hence, option D is correct

7 0
3 years ago
If I have 6.02x10^23 atoms of silicon, how many grams of silicon do I have?
Cerrena [4.2K]
You have 1 mol of silicon atoms.  Therefore you have its atomic mass in grams.  The answer is 28.055 g of silicon.
8 0
3 years ago
Which two element in the periodic table would you expect to combine in the most Violet foshion​
kotykmax [81]
H and O
CI and F
Mg and N
P and O
Cs and F
*should know them from the first letter very easy*
8 0
3 years ago
What is the maximum number of moles of PH 3 that can be formed when 0.2 formed moles of phosphorus reacts with 4 moles of hydrog
podryga [215]

Answer:

The maximum number of moles of PH₃ that can be formed is 0.8 moles.

Explanation:

The balanced reaction is:

P₄ + 6 H₂ → 4 PH₃

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of each compound participate in the reaction:

  • P₄: 1 mole
  • H₂: 6 moles
  • PH₃: 4 moles

The limiting reagent is one that is consumed first in its entirety, determining the amount of product in the reaction. When the limiting reagent is finished, the chemical reaction will stop.

To determine the limiting reagent, you can use a simple rule of three as follows: If by stoichiometry of the reaction 6 moles of hydrogen react with 1 mole of phosphorus, 4 moles of hydrogen will react with how many moles of phosphorus?

moles of phosphorus=\frac{4 moles of hydrogen*1 mole og phosphorus}{6moles of hydrogen}

moles of phosphorus= 0.667

But 0.667 moles of phosphorus are not available, 0.2 moles are available. Since you have less moles than you need to react with 4 moles of hydrogen, phosphorus will be the limiting reagent.

Then you can apply the following rule of three: if by stoichiometry 1 mole of P₄ forms 4 moles of PH₃, 0.2 moles of P₄ will form how many moles of PH₃?

moles of PH_{3} =\frac{0.2 moles of P_{4} *4 moles of PH_{3} }{1 mole of P_{4} }

moles of PH₃= 0.8

<u><em>The maximum number of moles of PH₃ that can be formed is 0.8 moles. </em></u>

<u><em></em></u>

4 0
3 years ago
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