<span>Stem cells begin to transfer into different types of cells in the human body in a process known as cell </span>differentiation.
<span>Cellular differentiation occurs throughout the cell development of a multi-cellular organism. It occurs when the cell changes from a simply zygote into a complex system of tissues and cell types. </span>
<span>Stems cells are cells which have the potential to develop into many different cell types in the body during early life and growth. Stem cells serve as internal repair system in many tissues. When stem cells divide while undergoing cell differentiation, it can either retain being a stem cell or become another type of cell like muscle cell, brain cell, or red blood cell.<span>
</span></span>
Answer:
14.14 m/s
Explanation:
As total mechanical energy is conserved, if the potential energy is the same at Chad's position no matter if the ball is travelling up or down, then its kinetic energy, and speed, is also the same too.
Therefore, the ball would have a speed of 10m/s when it's passing Chad the 1st time. Since we know that Chad is at 5m high from the release point, we can use the following equation of motion:
where v = 10 m/s is the velocity of the ball when it passes Chad, v_0 is the initial velocity of the ball when it releases, g = 10 m/s2 is the deceleration of the can, and is the distance traveled between Nicole and Chad. We can solve for v0:
Answer:
b. (4677)
Explanation:
You can apply the same equation we use to calculate the compound interest but with phones.
Look:
M = C.(1+i)^n
M = the total amount after 5 years
C = the firts amout of phones (285)
i = how much this number gets bigger (75%)
n = the number of periods (5 years)
So...
M = 285 . (1 + 0,75)^5
M = 285 . 1,75^5
M = 285 . 16.4
M = 4677
D thymine
if this is high school than i am tottaly right
When a small lab cart collide with a large mass then during the collision two bodies will remain in contact and then apply the contact force on each other
This contact force is always equal on two bodies in magnitude and also it is normal or perpendicular to the contact surface.
This will always follow Newton's III law as per which every action has equal and opposite reaction.
So this contact force will not depend on the mass or any other factor but it will remain same on two colliding bodies.
So here the correct answer would be
<em>They both experience the same magnitude of the collision force.
</em>