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fenix001 [56]
3 years ago
10

Find the pressure exerted by a force 8000 newton's on an area of 25m^2. Give your answer in newton's/n^2

Physics
1 answer:
Vanyuwa [196]3 years ago
5 0

The pressure exerted by this force is equal to 320 N/m^2.

<u>Given the following data:</u>

  • Force = 8000 Newton.
  • Area = 25 m^2.

To calculate the pressure exerted by this force:

<h3>How to calculate pressure.</h3>

Mathematically, pressure is given by this formula:

P=\frac{F}{A}

<u>Where:</u>

  • P is the pressure.
  • F is the force.
  • A is the area.

Substituting the given parameters into the formula, we have:

P = \frac{8000}{25}

P = 320 N/m^2.

Read more on pressure here: brainly.com/question/8033367

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7 0
4 years ago
I drop an egg from a certain distance and it takes the egg 3.74 seconds to reach the ground. How high up was the egg?
Ulleksa [173]

Answer:

<em>B. 68.6m</em>

Explanation:

<u>Free Fall Motion </u>

When a body is left to move in the air with no friction, the motion is ruled only by the force of gravity. The vertical distance a body travels in the air after a time t is .

\displaystyle y=\frac{gt^2}{2}

We know the egg takes 3.74 seconds to reach the ground. The height it was launched from is

\displaystyle y=\frac{(9.8)(3.474)^2}{2}

\displaystyle y=68.54\ m

The closest correct option is

B. 68.6m

5 0
3 years ago
What is general relativity in easy terms?
kirza4 [7]
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3 0
3 years ago
Read 2 more answers
А geostationary satellite moves in an orbit of radius 6300km. Calculate the speed with which it moves in the orbit [π=22÷7]​
azamat

Answer:

15.3 m/s

Explanation:

Radius of orbit= 6400+6300 = 12700 km

Circumference of orbit= 2*(22/7)*12700 =79796.45*10^3 m

Now,

       Speed= Distance / Time

                  = 79796.45*10^3/(24*60*3600)

                  = 15.3 m/s

4 0
3 years ago
A diverging lens of focal length 18.0m is used to view a shark that is 90.0m away from the lens. If the image formed is 1.0m lon
Reil [10]

Answer:

i. + 22.5 m ii. 4.0 m

Explanation:

i. Image distance

Using the lens formula

1/u + 1/v = 1/f where f = focal length = + 18.0 m, u = object distance = distance of shark away from lens = + 90.0 m and v = image distance from lens = unknown

So, we find v

1/v = 1/f - 1/u

= 1/+18 - 1/+90

= (5 - 1)/90

= 4/90

v = 90/4

= + 22.5 m

So the image is real and formed 22.5 m away on the other side of the lens.

ii Length of Shark

Using the magnification formula, m = image height/object height = image distance/object distance. image height = 1.0 m where object height = length of shark.

m = image distance/object distance

= v/u

= +22.5/+90

= 0.25

0.25 = image height/object height

So,

object height = image height/0.25

= 1.0 m/0.25

= 4.0 m

So, the length of the shark is 4.0 m

7 0
3 years ago
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