B would be the correct answer
Answer:
<h3>0.445</h3>
Explanation:
In friction, the coefficient of friction formula is expressed as;
![\mu = \frac{F_f}{R}](https://tex.z-dn.net/?f=%5Cmu%20%3D%20%5Cfrac%7BF_f%7D%7BR%7D)
Ff is the frictional force = Wsinθ
R is the reaction = Wcosθ
Substitute inti the equation;
![\mu = \frac{Wsin \theta}{W cos\theta} \\\mu = \frac{sin \theta}{cos\theta} \\\mu = tan \theta](https://tex.z-dn.net/?f=%5Cmu%20%3D%20%5Cfrac%7BWsin%20%5Ctheta%7D%7BW%20cos%5Ctheta%7D%20%5C%5C%5Cmu%20%3D%20%5Cfrac%7Bsin%20%5Ctheta%7D%7Bcos%5Ctheta%7D%20%5C%5C%5Cmu%20%3D%20tan%20%5Ctheta)
Given
θ = 24°
![\mu = tan 24^0\\\mu = 0.445\\](https://tex.z-dn.net/?f=%5Cmu%20%3D%20tan%2024%5E0%5C%5C%5Cmu%20%3D%200.445%5C%5C)
Hence the coefficient of kinetic friction between the box and the ramp is 0.445
Answer:
False statement = There must be a non-zero net force acting on the object.
Explanation:
An object is moving at a constant speed along a straight line. If the speed is constant then its velocity must be constant. We know that the rate of change of velocity is called acceleration of the object i.e.
![a=\dfrac{dv}{dt}](https://tex.z-dn.net/?f=a%3D%5Cdfrac%7Bdv%7D%7Bdt%7D)
a = 0
⇒ The acceleration of the object is zero.
The product of force and acceleration gives the magnitude of force acting on the object i.e.
F = m a = 0
⇒ The net force acting on the object must be zero.
So, the option (a) is not true. This is because the force acting on the object is zero. First option contradicts the fact.
D. They are heterotrophs that digest food internally.