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2 years ago

Find the pressure exerted by a force 8000 newton's on an area of 25m^2. Give your answer in newton's/n^2

Physics

1 answer:

Vanyuwa [196]2 years ago

5 0

The pressure exerted by this force is equal to 320 $N/m^2$ .

<u>Given the following data:</u>

Force = 8000 Newton.

Area = 25 $m^2$ .

To calculate the pressure exerted by this force:

<h3>How to calculate pressure.</h3>

Mathematically, pressure is given by this formula:

$P=\frac{F}{A}$

<u>Where:</u>

P is the pressure.

F is the force.

A is the area.

Substituting the given parameters into the formula, we have:

$P = \frac{8000}{25}$

P = 320 $N/m^2$ .

Read more on pressure here: brainly.com/question/8033367

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Minchanka [31]

Answer:

$F=43570.9N$

Explanation:

We can calculate the acceleration experimented by the passenger using the formula $v_f^2=v_i^2+2ad$ , taking the initial direction of movement as the positive direction and considering it comes to a rest:

$a=\frac{v_f^2-v_i^2}{2d}=\frac{-v_i^2}{2d}$

Then we use Newton's 2nd Law to calculate the force the passenger of mass m experimented to have this acceleration:

$F=ma=\frac{-mv_i^2}{2d}$

Which for our values is:

$F=\frac{-(65kg)(27.4m/s)^2}{2(0.56m)}=43570.9N$

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3 years ago

Two identical bowling balls are rolling on a horizontal floor without slipping. The initial speed of both balls is v = 10 m/s. B

Lapatulllka [165]

Answer:

The difference between frictionless ramp and a regular ramp is that on a frictionless ramp the ball cannot roll it can only slide, but on a regular ramp the ball can roll without slipping.

We will use conversation of energy.

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Note that initial potential energy is zero because the ball is on the bottom, and the final kinetic energy is zero because the ball reaches its maximum vertical distance and stops.

For the ball B;

$K_B_1 + U_B_1 = K_B_2 + U_B_2$

$\frac{1}{2}I_B\omega^2 + \frac{1}{2}mv^2 + 0 = 0 + mgH_B$

The initial velocities of the balls are equal. Their maximum climbing point will be proportional to their final potential energy. Since their initial kinetic energies are equal, their final potential energies must be equal as well.

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Explanation:

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3 years ago

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Explanation: In order to solve this problem we have to use the Gaussian law in diffrengios regions.

As we know,

∫E.dr= Qinside/εo

For r<a --->Qinside=0 then E=0

for a<r<b er have

E*2π*r*L= Q inside/εo in this case Qinside= ρ.Vol=ρ*2*π*r*(r-a)*L

E*2π*r*L =ρ*2*π*r* (r-a)*L/εo

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Finally for r>b

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2 years ago

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Answer:

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Given that

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Let's solve for y, first. We have

y = √[1 - (1.5*10^8²/3*10^8²)]

y = √(1 - ½²)

y = √(1 - ¼)

y = √0.75

y = 0.8660, using our newly gotten y, we use it to solve the final equation

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thus, we have found that the momentum of the particle is 129900 kgm/s

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3 years ago

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steposvetlana [31]

Answer:

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First, convert kg to g:

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Rounding to two significant figures, the density is 9.3 g/cm³.

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3 years ago