Based on the data provided, the impulse of the floor on the ball is 59.4 Ns.
<h3>What is the impulse of the floor on the ball?</h3>
Using the equation of motion to determine the velocity at the end of the fall
Where v is velocity at the end of fall
u is initial velocity = 0
g is acceleration due to gravity = 9.81 m/s^2
h is height = 20
- Taking downward velocity as negative and up as positive
v^2 = 0 + 2 (9.81)(20)
v^2 = 392.4
v = - 19.8 m/s
The velocity, v after bouncing is calculated also:
u = 0
g = 9.81 m/s^2
h = 5.0 m
v^2 = 0 + 2(9.81)(5)
v^2 = 98.1
v = 9.904 m/s
- Impulse = change in momentum
- Impulse = m(v- u)
Impulse = 2.0 × (9.9 -(-19.8)
Impulse = 59.4 Ns
Therefore, the impulse of the floor on the ball is 59.4 Ns.
Learn more about impulse at: brainly.com/question/904448
