Ask question

Ask question

All categories

4 years ago

7

A normal walking speed is around 2.0 m/s . how much time t does it take the box to reach this speed if it has the acceleration 5

.54 m/s2 that you calculated above?

1 answer:

creativ13 [48]4 years ago

6 0

Given:

u(initial velocity)=0

a=5.54m/s^2

v(final velocity)=2 m/s

v=u +at

Where v is the final velocity.

u is the initial velocity

a is the acceleration.

t is the time

2=0+5.54t

t=2/5.54

t=0.36 sec

You might be interested in

A spring has a 12 cm length. When a 200-g mass is hung from the spring, it extends to 27 cm. The hanging mass were pulled downwa

BartSMP [9]

Answer:

The equation of the time-dependent function of the position is $x(t)=5\cos(8.08t)$

(b) is correct option.

Explanation:

Given that,

Length = 12 cm

Mass = 200 g

Extend distance = 27 cm

Distance = 5 cm

Phase angle =0°

We need to calculate the spring constant

Using formula of restoring force

$F=kx$

$mg=kx$

$k=\dfrac{mg}{x}$

$k=\dfrac{200\times10^{-3}\times9.8}{(27-12)\times10^{2}}$

$k=13.06\ N/m$

We need to calculate the time period

Using formula of time period

$T=2\pi\sqrt{\dfrac{m}{k}}$

Put the value into the formula

$T=2\pi\sqrt{\dfrac{0.2}{13.6}}$

$T=0.777\ sec$

At t = 0, the maximum displacement was 5 cm

So, The equation of the time-dependent function of the position

$x(t)=A\cos(\omega t)$

Put the value into the formula

$x(t)=5\cos(2\pi\times f\times t)$

$x(t)=5\cos(2\pi\times\dfrac{1}{T}\times t)$

$x(t)=5\cos(2\pi\times\dfrac{1}{0.777}\times t)$

$x(t)=5\cos(8.08t)$

Hence, The equation of the time-dependent function of the position is $x(t)=5\cos(8.08t)$

8 0

3 years ago

Which one of the following is an example of an acid-base reaction?

Lina20 [59]

Answer:

A. 2HCl + Mg(OH)2 + 2H2O + MgCl2

hope it helps

6 0

3 years ago

Can someone help?? 3/5

ycow [4]

Answer:

Yes to answer is 3/5 of what

8 0

3 years ago

Elements X and Y have atomic number of 11 and 17 respectively. Which one of the elements is a metal?

lianna [129]

Answer:

atomic 11

Explanation:

atomic 11 Na is metal

3 0

3 years ago

You are given a sample of metal and asked to determine its specific heat. You weigh the sample and find that its weight is 27.2

garri49 [273]

Answer:

c=326.5177 J/kg.K

Specific heat is c=326.5177 J/kg.K

Explanation:

In order ti find the specific heat, we will proceed as follow:

Formula we are going to use is:

$Q=m*c*\Delta T$

Where:

Q is the heat energy added

m is the mass of sample

c is the specific heat

$\Delta T$ is the temperature Rise.

First we will find the mass:

Weight=m*g (g is gravitational acceleration=9.8 m/s^2)

$m=\frac{weight}{g} \\m=\frac{27.2}{9.8} \\m=2.7755 \ kg$

Rearranging above formula:

$c=\frac{Q}{m* \Delta T}$

$c=\frac{1.45*10^4}{2.7755*16}$

c=326.5177 J/kg.K

Specific heat is c=326.5177 J/kg.K

5 0

3 years ago