3 years ago

I need help w these 2 questions

Chemistry

1 answer:

tia_tia [17]3 years ago

7 0

Answer:

1. a = 2, b = 1 and c = 2

2. a = 1, b = 3, c = 2 and d = 2

Explanation:

According to law of conservation of mass, the mass can neither be created nor destroyed.

Hence, for a chemical equation the left hand side should be equal to the right hand side.

Therefore, the two balanced equations are;

2 CO + O₂ → 2 CO₂

C₂H₄ + 3 O₂ → 2 CO₂ + 2 H₂O

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What is the percent of aluminum in al2(so4)3

Lena [83]

Answer : The percent of aluminium in $Al_2(SO_4)_3$ is $15.77\%$

Solution :

Molar mass of Aluminium = 26.98 g/mole

Molar mass of $Al_2(SO_4)_3$ = 342.15 g/mole

First we have to calculate the mass of Aluminium.

Mass of 2 Al atoms = 2 × 26.98 g/mole = 53.96 g/mole

Now we have to calculate the percent composition of Aluminium in $Al_2(SO_4)_3$

$\%\text{ of Al}=\frac{\text{ Mass of Al}}{\text{ Total mass}}\times 100$

Now put all the given values in this formula, we get

$\%\text{ of Al}=\frac{53.96g/mole}{342.15g/mole}\times 100$

$\%\text{ of Al}=15.77\%$

Therefore, the percent of aluminium in $Al_2(SO_4)_3$ is $15.77\%$

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I need help w these 2 questions​

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