Answer:
A ∩ B = {1, 3, 5}
A - B = {2, 4}
Step-by-step explanation:
The given problem regards sets and set notation, a set can simply be defined as a collection of values. One is given the following information:
A = {1, 2, 3, 4, 5}
B = {1, 3, 5, 6, 9}
One is asked to find the following:
A ∩ B,
A - B
1. Solving problem 1
A ∩ B,
The symbol (∩) in set notation refers to the intersection between the two sets. It essentially asks one to find all of the terms that two sets have in common. The given sets (A) and (B) have the values ({1, 3, 5}) in common thus, the following statement can be made,
A ∩ B = {1, 3, 5}
2. Solving problem 2
A - B
Subtracting two sets is essentially taking one set, and removing the values that are shared in common with the other set. Sets (A) and (B) have the following values in common ({1, 3, 5}). Thus, when doing (A - B), one will omit the values ({1, 3, 5}) from set (A).
A - B = {2, 4}
3(x+6)=-24
Divide both sides by 3
3(x+6)/3=-24/3
X+6=-8
X=-14
5% of $50 = 5/100 x 50 = $2.50
Total = 50 + 2.50 = $52.50
The saes tax is $2.50; her total cost of the shirt is $52.50
Answer:
The answer is below
Step-by-step explanation:
Let x represent the cost of 1 scoop of ice cream. Since the cost of 2 scoops of ice cream are twice the price of 1 scoop of ice cream, therefore the cost of 2 scoops of ice cream = 2x
Jean buys 4 tubs with 2 scoops in them and 2 tubs with 1 scoop each. Therefore the money spent by Jean is:
Money spent by Jean = 4(2x) + 2(x) = 8x + 2x = 10x
Sarah buys 2 tubs of 2 scoops and 4 tubs of 1 scoop. The money spent by Sarah is:
Money spent by Sarah = 2(2x) + 4(x) = 4x + 4x = 8x
Sarah spends 2.50 € less than Jean. Therefore:
Money spent by Sarah = Money spent by Jean - 2.5
8x = 10x - 2.5
2x = 2.5
x = €1.25
Therefore the cost of 1 scoop of ice cream is €1.25, the cost of 2 scoops of ice cream is €2.50.
Money spent by Jean = 10x = 10(1.25) = €12.5
Money spent by Sarah = 8x = 8(1.25) = €10
Answer:
92
Step-by-step explanation:
5 times 18=90
90+2=92
you do times first because order of operations.