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Valentin [98]
3 years ago
13

2. Which of the following solution contains more salt? A. 3M B. 1M C. 0.5M D. 0.25M

Chemistry
1 answer:
Tanya [424]3 years ago
5 0

Answer: 0.25M

Explanation: Because of the highest concentration of water and, if they are all the same volume, the greatest amount of water assuming it is a solid solute in a water solution.

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What is the difference between intermolecular forces and intramolecular forces
MrMuchimi

Answer:

Intramolecular forces are the forces that hold atoms together within a molecule. Intermolecular forces are forces that exist between molecules.

Explanation:

Examples: Intermolecular forces are categorized into dipole-dipole forces, London dispersion forces and hydrogen bonding forces.

Intramolecular forces are categorized into covalent, ionic and metal bonds

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2 years ago
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Which lists the elements in order from least conductive to most conductive?
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Answer: Option (A) is the correct answer.

Explanation:

Nitrogen is a non-metal and it is known that non-metals do not conduct electricity. Thus, it will be least conductive out of the given options.

Whereas antimony (Sb) is a metalloid. Metalloid are the substance that show properties of both metals and non-metals. Thus, antimony will conduct electricity.

On the other hand, bismuth (Bi) is a metal hence, it will conduct electricity.

Thus, we can conclude that the order from least conductive to most conductive will be nitrogen (N), antimony (Sb), bismuth (Bi).

 

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3 years ago
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If you have 16 g of manganese (II) nitrate tetrahydrate, how much water is required to prepare 0.16 M solution from this amount
Schach [20]

<u>Answer:</u> The amount of water required to prepare given amount of salt is 398.4 mL

<u>Explanation:</u>

To calculate the volume of solution, we use the equation used to calculate the molarity of solution:

\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}

We are given:

Molarity of solution = 0.16 M

Given mass of manganese (II) nitrate tetrahydrate = 16 g

Molar mass of manganese (II) nitrate tetrahydrate = 251 g/mol

Putting values in above equation, we get:

0.16M=\frac{16\times 1000}{251\times \text{Volume of solution}}\\\\\text{Volume of solution}=\frac{16\times 1000}{251\times 0.16}=398.4mL

Volume of water = Volume of solution = 398.4 mL

Hence, the amount of water required to prepare given amount of salt is 398.4 mL

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D

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