Electrolyte is any species which when dissolved in solvent particularly water dissociates into cations and anions. Electrolytes are conductors of electricity. In given options;
CCl₄ (Tetrachloromethane) is a covalent compound. And it doesn't dissociate to any cation or anion. So it is not electrolyte.
SiO₂ (Silicon Dioxide) is also covalent in nature and exist in giant framework. It is not electrolyte.
Glucose (C₆H₁₂O₆) is also covalent compound. And doesn't produced any ion in water, hence it is not electrolyte.
H₂SO₄ (Sulfuric acid) is Electrolyte. When it is dissolved in water it produces H⁺ and SO₄²⁻ ions as follow,
H₂SO₄ → 2 H⁺ ₍aq₎ + SO₄²⁻ ₍aq₎
Result:
H₂SO₄ is electrolyte.
Answer:
Requires two Mg²⁺ cofactors and as such demonstrates metal-ion catalysis
Explanation:
Electrostatic catalysis or metal ion catalysis is a catalytic mechanism that makes use of metalloenzymes, such as enolase along with a metal ion which is bound tightly, including, Mo⁶⁺, Ni³⁺, Co³⁺, Mn²⁺, Zn²⁺, Cu²⁺, and Fe²⁺, to undertake a catalysis
For maximal activity, enolase requires the presence of 2 equivalent metal ions in each site which is active
Therefore, the correct option is; requires two Mg²⁺ cofactors and as such demonstrates metal-ion catalysis
Answer:
d. Copper (II) sulfate
Explanation:
Given data:
Mass of Al = 1.25 g
Mass of CuSO₄ = 3.28 g
What is limiting reactant = ?
Solution:
Chemical equation:
2Al + 3CuSO₄ → Al₂ (SO₄)₃ + 3Cu
Number of moles of Al:
Number of moles = mass/molar mass
Number of moles = 1.25 g/ 27 g/mol
Number of moles = 0.05 mol
Number of moles of CuSO₄:
Number of moles = mass/molar mass
Number of moles = 3.28 g/ 159.6 g/mol
Number of moles = 0.02 mol
now we will compare the moles of reactant with product.
Al : Al₂ (SO₄)₃
2 : 1
0.05 : 1/2×0.05=0.025 mol
Al : Cu
2 : 3
0.05 : 3/2×0.05 = 0.075 mol
CuSO₄ : Al₂ (SO₄)₃
3 : 1
0.02 : 1/3×0.02=0.007 mol
CuSO₄ : Cu
3 : 3
0.02 : 0.02
Less number of moles of reactants are produced by CuSO₄ thus it will act as limiting reactant.
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