3 years ago

It takes 700 joules to lift an object straight up, but 1400 joules to push it up a ramp, what is the

Physics

1 answer:

crimeas [40]3 years ago

3 0

Answer:

561

Explanation: it would most definitely go down as a number because it isn't the same

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A 0.14-km wide river flows with a uniform speed of 4.0 m/s toward the east. It takes 20 s for a boat to cross the river to a poi

Dmitry [639]

Answer:

The right approach is "8.1 m/s". A further explanation is provided below.

Explanation:

According to the table,

Speed of Boat

= $\frac{s}{t}$

$V_b=\frac{140}{20}$

$V_a = 4 \ m/s$

$V_B = 7 \ m/s$

Now,

⇒ $(V_{relative})^2 = (7)^2+(4)^2$

or,

⇒ $(V_r)^2=49+16$

$=65$

$V_r=\sqrt{65}$

$=8.1 \ m/s$

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3 years ago

Why does green light slow down more than orange light does when passing through an object?

jeka94

Because when a white light goes through a clear object like the glass pyrimide it divides into the different color lights the different color lights travel in different speeds like the red light traveles faster that the purple light thats why on a rainbow the red is on the top and purple is on the bottom
HOPE THIS HELPED

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3 years ago

Read 2 more answers

In what direction would the new b field point?

Aleonysh [2.5K]

Please include more information about the problem. What "b field" are you talking about? What is different about it from the previous field?

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3 years ago

At mass = 500g, what is the volume

satela [25.4K]

With what you have here, there is no way to determine the volume. Do you have the density also?

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3 years ago

A heat engine operates in a Carnot cycle between 75◦C and 492◦C. It absorbs 19300 J of energy per cycle from the hot reservoir.

Nitella [24]

Answer:

9.069 KW

Explanation:

The heat engine operates in a carnot cycle between 75°C to 492°C so the lower temperature $T_L=75^{\circ}C=273+75=348K$ and the higher temperature $T_H=492^{\circ}C=273+492=765K$

Efficiency of the carnot cycle $\eta =1-\frac{T_L}{T_H}=1-\frac{348}{765}=0.545$

We know that $\eta =\frac{work\ done }{heat\ absorbed}$

$work\ done=\eta \times heat\ abosorbed=0.545\times 19300=10520.392\ J$

it is given that duration of each cycle is 1.16 sec so power output $P=\frac{W}{T}=\frac{10520.392}{1.16}=9069.30\ W=9.069\ KW$

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3 years ago